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mihalych1998 [28]

1 year ago

5

The current in two identical light bulbs connected in series is 0. 25 A. The voltage across both bulbs is 110 V. The resistance

of a single light bulb is

1 answer:

konstantin123 [22]1 year ago

8 0

Answer:

220 ohms

Explanation:

I = V / R

0.25 = 110 / R

R = 110 / 0.25

R = 440 ohms

Equivalent resistance = 440 ohms

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2

= 220 ohms

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