Ball rolls down ramp, ball is released from spring, ball drops down chute.
Answer:
θ = 18.3°
Explanation:
The angle can be found by using the formula for the range of projectile motion:
where,
R = Horizontal Range = 8.75 m
u = launch speed = 12 m/s
g = acceleration due to gravity = 9.81 m/s²
θ = launch angle = ?
Therefore,
θ = 18.3°
Since this angle is less than 45°. Therefore, it is the smaller of the two possible angles an dit is the correct answer:
<u>θ = 18.3°</u>
Answer:
Explanation:
Let Vc be the velocity of the car and Vm the velocity of the motorcycle. If we convert their given values, we get:
Vc = 87 km/h * 1000m / 1km * 1h / 3600s = 24.17m/s
Vm = 95 km/h * 1000m / 1km * 1h / 3600s = 26.38m/s
Since their positions are equal after 17s we can stablish that:
Where d is the initial separation distance of 54m. Solving for a, we get:
Repacing the values: