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mihalych1998 [28]
2 years ago
5

The current in two identical light bulbs connected in series is 0. 25 A. The voltage across both bulbs is 110 V. The resistance

of a single light bulb is
Physics
1 answer:
konstantin123 [22]2 years ago
8 0

Answer:

220 ohms

Explanation:

I = V / R

0.25 = 110 / R

R = 110 / 0.25

R = 440 ohms

Equivalent resistance = 440 ohms

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2

= 220 ohms

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Do atoms have full outer energy level combine with other atoms
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3 years ago
An infinitely long line of charge has linear charge density 6.00×10−12 C/m . A proton (mass 1.67×10−27 kg,charge +1.60×10−19 C)
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A) \,K.E=1.405\times 10^{-20}J

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Charge\,\,density=\lambda=6\times 10^{-12}C/n\\\\Mass\,\, of \,\,proton=m_p=1.67\times 10^{-27}kg\\\\charge\,\, of\,\, proton=q_p=1.609\times 10^{-19}C\\\\r=12\,cm=0.12\, m\\\\v=4.103\times 10^{3}m/s

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B) How close does the proton get to the line of charge?

Potential energy and kinetic energy are related as:

K_i+U_i=K_f+U_f\\\\U_f-U_i=K_i-K_f\\\\q(V_f-V_i)=1.40\times 10^{-20}\\\\V_f-V_i=0.087--(1)\\

Change in voltage is

V_f-V_i=\frac{\lambda}{2\pi \epsilon_o}ln\frac{r_f}{r_i}\\\\ln|\frac{r_f}{r_i}|=(0.087)(\frac{2\pi \epsilon_o}{\lambda})\\\\ln|\frac{r_f}{r_i}|==0.8059\\\\\frac{r_f}{r_i}=2.24\\\\r_f=(2.24)(.12)\\\\r_f=0.268 m

5 0
3 years ago
When a medium is disturbed by a wave, does it move with the wave?
DerKrebs [107]

Answer:

As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave. Only the energy of the wave travels through the medium

8 0
3 years ago
A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn doo
Tresset [83]

Answer:

The work done is -209.42 J.

Explanation:

F(x) = (- 20 - 3 x ) N

x = 0 to x = 6.9 m

Here, the force is variable in nature, so the work done by the variable force is given by

W =\int F dx\\\\W =\int_{0}^{6.9}(-20- 3x dx )\\\\W= \left [ - 20 x - 1.5 x^2 \right ]_{0}^{6.9}\\\\W = - 20 (6.9 - 0) - 1.5(6.9\times 6.9 - 0)\\\\W =- 138 - 71.42\\\\W = - 209.42  J

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3 years ago
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