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Ksenya-84 [330]
3 years ago
13

The extraction of aluminum metal from the aluminum hydroxide in bauxite ore by the Hall-Héroult process is one of the most remar

kable success stories of late 19th century practical chemistry, turning aluminum from a rare and precious metal into the cheap commodity it is today. In the first step, aluminum hydroxide reacts to form alumina and water: 2AlOH3(s)→Al2O3(s)+3H2O(g) In the second step, alumina and carbon react to form aluminum and carbon dioxide: 2Al2O3(s)+3C(s)→4Al(s)+3CO2(g) Write the net chemical equation for the production of aluminum from aluminum hydroxide and carbon. Be sure your equation is balanced.
Chemistry
1 answer:
allochka39001 [22]3 years ago
8 0

<u>Answer:</u> The net chemical equation for the  production of aluminium from aluminium hydroxide and carbon is 2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

<u>Explanation:</u>

The given intermediate reactions are:

<u>Step 1:</u>  2Al(OH)_3(s)\rightarrow Al_2O_3(s)+3H_2O(g)

<u>Step 2:</u>  2Al_2O_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)

By combining these two above equations, we will get the net chemical equation for the production of aluminium from aluminium hydroxide and carbon.

The net chemical equation follows:

2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

Hence, the net chemical equation for the  production of aluminium from aluminium hydroxide and carbon is 2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

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Its destructing the nature
5 0
2 years ago
What happens when an electron moves from a high energy level to a lower one? it absorbs light it emits light it disappears it ge
Marianna [84]

Answer: The correct answer is it emits light.

Explanation:

When an electron is present in ground level that is the lower energy level and moves to the higher energy level, the energy is provided to the electron which means that it absorbs light. This is known as absorption.

When an electron present in the higher energy level comes back to the lower energy level, it emits radiations in the form of light. This is known as emission.

Hence, the correct answer is it emits light.

8 0
3 years ago
In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.
olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

A=\pi ^{1/3} (6V)^{2/3}

The area of the 10.0 cm³-sphere is:

A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}

The area of each 1.25 cm³-sphere is:

A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of  8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

6 0
3 years ago
Consider the balanced equation for the following reaction:
Bad White [126]

<u>Answer:</u> The theoretical yield of the lithium chlorate is 1054.67 grams

<u>Explanation:</u>

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Actual moles of lithium chlorate = 9.45 moles

Molar mass of lithium chlorate = 90.4 g/mol

Putting values in above equation, we get:

9.45mol=\frac{\text{Actual yield of lithium chlorate}}{90.4g/mol}\\\\\text{Actual yield of lithium chlorate}=(9.45mol\times 90.4g/mol)=854.28g

To calculate the theoretical yield of lithium chlorate, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Actual yield of lithium chlorate = 854.28 g

Percentage yield of lithium chlorate = 81.0 %

Putting values in above equation, we get:

81=\frac{854.28g}{\text{Theoretical yield of lithium chlorate}}\times 100\\\\\text{Theoretical yield of lithium chlorate}=\frac{854.28\times 100}{81}=1054.67g

Hence, the theoretical yield of the lithium chlorate is 1054.67 grams

7 0
2 years ago
Be sure to answer all parts. this is a two-part question. first, draw the minor alkene product that should be formed in the reac
kotykmax [81]

Answer:

See explanation below

Explanation:

The question is incomplete, however, I found a question very similar to this, and I'm assuming this is the question you are asking to answer. If it's not, please tell me which one it is. Here's a tip for you to get an idea of how to solve.

Picture 1, would be the original question. Picture 2 is the answer of it.

Now, This is a E1 reaction where this type of reactions are taking place in two steps. The first step is the formation of the carbon cation, this step is always slow. The secon step is the addition of a nucleophyle, or, in this case, formation of a pi bond, and we get a alkene.

Hope this can help you

8 0
2 years ago
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