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Ksenya-84 [330]
4 years ago
13

The extraction of aluminum metal from the aluminum hydroxide in bauxite ore by the Hall-Héroult process is one of the most remar

kable success stories of late 19th century practical chemistry, turning aluminum from a rare and precious metal into the cheap commodity it is today. In the first step, aluminum hydroxide reacts to form alumina and water: 2AlOH3(s)→Al2O3(s)+3H2O(g) In the second step, alumina and carbon react to form aluminum and carbon dioxide: 2Al2O3(s)+3C(s)→4Al(s)+3CO2(g) Write the net chemical equation for the production of aluminum from aluminum hydroxide and carbon. Be sure your equation is balanced.
Chemistry
1 answer:
allochka39001 [22]4 years ago
8 0

<u>Answer:</u> The net chemical equation for the  production of aluminium from aluminium hydroxide and carbon is 2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

<u>Explanation:</u>

The given intermediate reactions are:

<u>Step 1:</u>  2Al(OH)_3(s)\rightarrow Al_2O_3(s)+3H_2O(g)

<u>Step 2:</u>  2Al_2O_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)

By combining these two above equations, we will get the net chemical equation for the production of aluminium from aluminium hydroxide and carbon.

The net chemical equation follows:

2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

Hence, the net chemical equation for the  production of aluminium from aluminium hydroxide and carbon is 2Sl(OH)_3(s)+3C(s)\rightarrow 4Al(s)+3CO_2(g)+3H_2O(g)

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mrs_skeptik [129]

Answer:

1

Explanation:

outershell atoms of an element are also known as valency of that element

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miss Akunina [59]

Answer: I'm sure it is c

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Describe the radial velocity curve. What is its shape? What is its amplitude? What is the orbital period?
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Answer:

The radial velocity curve describes how fast a star is moving in its orbit around a center of mass ( m )

Curve amplitude : This is the maximum value of the radial velocity curve

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The radial velocity curve describes how fast a star is moving in its orbit around a center of mass ( m ) while Curve amplitude  is the maximum value of the radial velocity curve also The shape of Radial velocity curve is parabolic in nature. and  Orbital period is the time taken by the star  to make one complete rotation in its orbit

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3 years ago
Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe
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Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

c = \frac{n}{V}

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}

M_{KOH} = 56.106 \frac{g}{mol}

<u>Calculate the moles of potassium hydroxide.</u>

n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}

n_{KOH} = 0.25941(9)mol

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

V = \frac{500.0mL}{1}*\frac{1L}{1000mL}

V = 0.5000L

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

c = \frac{n}{V}

c = \frac{0.25941(9)mol}{0.5000 L}              

c = 0.5188(3) \frac{mol}{L}         <= Keep an insignificant figure for rounding

c = 0.5188 \frac{mol}{L}              <= Rounded up

c = 0.5188M               <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

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