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kipiarov [429]
3 years ago
5

At what point is a base no longer added during a titration?

Chemistry
2 answers:
Finger [1]3 years ago
7 0

Answer:

A on Edge

Explanation:

nordsb [41]3 years ago
6 0

Answer:

when the pH increases suddenly in the flask

Explanation:

I think it's right. :)

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babunello [35]

Answer:

John Dalton

Explanation:

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4 years ago
Can you provide an example for both fission and fusion
dsp73
Fission energy is gained by splitting apart heavy atoms fusion is combining light atoms
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3 years ago
Jenna built the electrical circuit seen here. What would happen to the electrical energy if Jenna removed one of the clips on th
otez555 [7]

Answer: Option (D) is the correct answer.

Explanation:

An electric circuit works well when all the connections are complete but if any of the connections in the circuit is loose or disconnected then it is possible that current will not flow from the circuit.

Therefore, when Jenna removed one of the clips on the battery then circuit becomes incomplete and as a result there will no flow of current.

Thus, we can conclude that the electrical energy would stop because the circuit is incomplete.

6 0
3 years ago
The volume of a sample of oxygen is 300.0 mL when the pressure is 1.00 atm and the temperature is 27.0°C. At what temperature is
Zina [86]
2.5 i believe i'll keep you updated i'm still trying to check my answers
7 0
3 years ago
1.
GarryVolchara [31]

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3}

V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3}

The total volume is given by:

V_{T} = V_{o} - V_{i}

Where:

V_{i}: is the inner volume

r_{i}: is the inner radius = 1.25/2 = 0.625 m

V_{o}: is the outer volume

r_{o}: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}

Now, by using the density we can find the mass of the Igloo:

m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g

Finally, the value (V) of the antiquity is:

V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6}  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

8 0
3 years ago
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