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Nuetrik [128]
3 years ago
8

I need help ASAP pls. ​

Mathematics
1 answer:
marusya05 [52]3 years ago
4 0
With which question?
You might be interested in
Our class has 50 students. Assuming that no students are born on leap days (February29), what is the probability that no two stu
madreJ [45]

Answer:  a) \dfrac{799}{31250}  b) \dfrac{30451}{31250}

Step-by-step explanation:

Since we have given that

Number of days in a year = 365

Number of students = 50

Probability that no two students share the same birthday. It means each student has different birthday.  

Probability(no two students share the same birthday)=\dfrac{365-1}{365}\times \dfrac{365-2}{365}........\times \dfrac{365-50}{365}

Probability(no two students share the same birthday)=\dfrac{^{365}P_{50}}{365^{50}}

Probability(no two students share the same birthday)=\dfrac{799}{31250}\approx 0.025568

Probability that at least one of the students has the same birthday as another student in the class is given by

1-P(\text{no student share the same birthday})\\\\=1-\dfrac{799}{31250}\\\\=\dfrac{30451}{31250}=0.974432

5 0
3 years ago
Use abc to find the value of cos B
krok68 [10]
Cos of b equals c over a 
7 0
3 years ago
Bailey buys a car for $18,000 and it has a depreciation value of 16% per year after 3
sergiy2304 [10]

Answer:

$10668.67

Step-by-step explanation:

If the car value goes down 16% each year, after the first year, it will be worth 1520.

The next year, it will be worth $12700.80

After the third year, the car will be worth $10,668.67

5 0
2 years ago
WHAT NUMBER IS MISSING IN THE FOLLOWING SERIES: 4 --‐ 5 --‐ 7 --‐ 10 --‐ 14 --‐ 19 --‐ ___
Kruka [31]

Answer:

25

simple, when you add another number into the sequence, it is increased by 1 per each number...

3 0
3 years ago
25 – 4.33<br>7 + (1 - 100)​
Sidana [21]

Answer:

25 – 4.33 = 20.67

7 + (1 - 100)​ = -92

Step-by-step explanation:

First one) Simply use your knowledge of integers and decimals to solve this. You can even start by drawing a number line and practising with that before beginning to do harder problems.

Second one) Just like the first one but use PEDMAS, BEDMAS or BODMAS and make sure to solve the brackets first.

6 0
3 years ago
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