All categories

3 years ago

How long will the ball be in the air if the cliff is 120 m tall and the ball falls to the base of the cliff?

Physics

1 answer:

Readme [11.4K]3 years ago

3 0

Answer:

Explanation:

4.95s≈5s

Use equation :

h=G*t²/2

h=120m ----hight of cliff

G=9.81m/s²

t=?

-----------------------

h=G*t²/2

120m=9.81m/s²*t²/2

240m=9.81m/s²*t²

t²=240m/ 9.81m/s²

t²=24.46s

t=√24.46s²

t=4.95 s≈5s

You might be interested in

What should be the spring constant k of a spring designed to bring a 1200 kg car to rest from a speed of 85 km/h so that the occ

borishaifa [10]

Answer:

k = 5178.8 N/m

Explanation:

As we know that spring mass system will oscillate at angular frequency given as

$\omega = \sqrt{\frac{k}{m}}$

now we have

$\omega = \sqrt{\frac{k}{1200}}$

now the maximum acceleration of the spring block system is at its maximum compression state which is given as

$a = \omega^2 A$

here A= maximum compression of the spring

so here in order to find maximum compression of the spring we will use energy conservation as we know that initial total kinetic energy of the car will convert into spring potential energy

$\frac{1}{2}mv^2 = \frac{1}{2}kA^2$

here we know that

v = 85 km/h

$v = 85 \times\frac{1000}{3600} = 23.61 m/s$

now we have

$(1200)(23.61^2) = kA^2$

$A^2 = \frac{6.68 \times 10^5}{k}$

now from above equation of acceleration we have

$5.0 g = (\frac{k}{m})\sqrt{\frac{6.68 \times 10^5}{k}}$

$5.0(9.81) = \sqrt{k}(0.68)$

$k = 5178.8 N/m$

6 0

3 years ago

An electron enters a region of space containing a uniform 0.0000193-T magnetic field. Its speed is 121 m/s and it enters perpend

Mandarinka [93]

Answer

Given,

Magnetic field, B = 0.0000193 T

speed, v = 121 m/s

mass of electron, m = 9.11 x 10⁻³¹ Kg

charge of electron, q = 1.6 x 10⁻¹⁹ C

radius of the electron path, r = ?

$r = \dfrac{mv}{qB}$

$r = \dfrac{9.31\times 10^{-31}\times 121}{1.6\times 10^{-19}\times 0.0000193}$

r = 3.64 x 10⁻⁵ m

We know frequency is inverse of time period

d = v t

$2 \pi r = v \times t$

$t = \dfrac{2 \pi r}{v}$

$t = \dfrac{2 \pi \times 3.64\times 10^{-5}}{121}$

t = 1.889 x 10⁻⁶ s.

now, frequency

$f = \dfrac{1}{t}$

$f = \dfrac{1}{1.889\times 10^{-6}}$

$f = 529380\ Hz$

3 0

3 years ago

This diagram shows the process that powers stars. This process is called?

viktelen [127]

The process that powers stars is C)fusion

4 0

2 years ago

Read 2 more answers

Ganezh [65]

Answer:

A. topsoil the answer

Explanation:

I think its a correct answer

3 0

2 years ago

Ryan runs 50 m north and then 50 m east. What is his displacement?

san4es73 [151]

Answer:

Explanation:

Distance and direction of an object's change in position from a starting point. Displacement. 3. Jermaine runs exactly 2 laps around a 400 meter track. What is the displacement? 0 ... David walks 3 km north, and then turns east and walks 4 km. ... A person walks 50 meters directly north, stops, and then travels 32 meters

3 0

2 years ago