Answer:
a) 29.36 m
b) 2.44 s
c) 2.57 s
d) 25.117 m/s
Explanation:
t = Time taken
u = Initial velocity = 24 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
b)
![v=u+at\\\Rightarrow 0=24-9.81\times t\\\Rightarrow \frac{-24}{-9.81}=t\\\Rightarrow t=2.44 \s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%200%3D24-9.81%5Ctimes%20t%5C%5C%5CRightarrow%20%5Cfrac%7B-24%7D%7B-9.81%7D%3Dt%5C%5C%5CRightarrow%20t%3D2.44%20%5Cs)
Time taken by the ball to reach the highest point is 2.44 seconds
a)
![s=ut+\frac{1}{2}at^2\\\Rightarrow s=24\times 2.44+\frac{1}{2}\times -9.81\times 2.44^2\\\Rightarrow s=29.35\ m](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20s%3D24%5Ctimes%202.44%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20-9.81%5Ctimes%202.44%5E2%5C%5C%5CRightarrow%20s%3D29.35%5C%20m)
The highest point reached by the ball above its release point is 29.36 m
c) Total height is 3+29.35 = 32.35 m
![s=ut+\frac{1}{2}at^2\\\Rightarrow 32.35=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{32.35\times 2}{9.81}}\\\Rightarrow t=2.57\ s](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%2032.35%3D0t%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.81%5Ctimes%20t%5E2%5C%5C%5CRightarrow%20t%3D%5Csqrt%7B%5Cfrac%7B32.35%5Ctimes%202%7D%7B9.81%7D%7D%5C%5C%5CRightarrow%20t%3D2.57%5C%20s)
The ball reaches the ground 2.57 seconds after reaching the highest point
d)
![v=u+at\\\Rightarrow v=0+9.81\times 2.57\\\Rightarrow v=25.2117\ m/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D0%2B9.81%5Ctimes%202.57%5C%5C%5CRightarrow%20v%3D25.2117%5C%20m%2Fs)
The ball will hit the ground at 25.2117 m/s
Assuming that the magnitude is additive, then you simply have to add the brightness four times. This is because each star has 2 magnitudes of 8.34. As a result, you have to add 4 magnitudes of 8.34. The solution is as follows:
Magnitude = 4(8.34)
Magnitude = 33.36
Answer:
5.71428571422 m/s
Explanation:
u = Initial velocity = 20 m/s
v = Final velocity
s = Displacement
a = Acceleration
Time taken = 15-1 = 14 s
Distance traveled in 1 second = ![20\times 1=20\ m](https://tex.z-dn.net/?f=20%5Ctimes%201%3D20%5C%20m)
![s=ut+\frac{1}{2}at^2\\\Rightarrow 200-20=20\times 14+\frac{1}{2}\times a\times 14^2\\\Rightarrow a=\frac{2(180-20\times14)}{14^2}\\\Rightarrow a=-1.02040816327\ m/s^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5CRightarrow%20200-20%3D20%5Ctimes%2014%2B%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20a%5Ctimes%2014%5E2%5C%5C%5CRightarrow%20a%3D%5Cfrac%7B2%28180-20%5Ctimes14%29%7D%7B14%5E2%7D%5C%5C%5CRightarrow%20a%3D-1.02040816327%5C%20m%2Fs%5E2)
![v=u+at\\\Rightarrow v=20-1.02040816327\times 14\\\Rightarrow v=5.71428571422\ m/s](https://tex.z-dn.net/?f=v%3Du%2Bat%5C%5C%5CRightarrow%20v%3D20-1.02040816327%5Ctimes%2014%5C%5C%5CRightarrow%20v%3D5.71428571422%5C%20m%2Fs)
The speed as she reaches the light at the instant it turns green is 5.71428571422 m/s
Answer:
option (a)
Explanation:
Wavelength is defined as the distance traveled by the wave in one complete oscillation.
The number of oscillations completed in one second is called frequency.
The relation for the wave velocity is given by
wave velocity = frequency x wavelength
Outcome- possible results of an experiment is called an outcome.
ex- 2 is a possible outcome when a number cube is rolled