2 years ago

Pls help me with this

Chemistry

2 answers:

liubo4ka [24]2 years ago

6 0

Answer:

silver

5/20

=0.25.................

Sunny_sXe [5.5K]2 years ago

4 0

Answer:

Explanation:

Aluminum density = 0.5

Iron density = 2

Gold density = 1

Silver density = 0.25

The smallest value is 0.25 hence silver has less density.

You might be interested in

PLZ HELP ME What are the five shared characteristics of all living things?

djverab [1.8K]

Answer:

Explanation:

I believe the answer is D.

5 0

3 years ago

What is the name of the process during which a bond between two monomers is broken?

Snezhnost [94]

Answer: D, hydrolysis

Hydrolysis is any chemical reaction in which a molecule of water ruptures one or more chemical bonds. The term is used broadly for substitution, elimination, and fragmentation reactions in which water is the nucleophile.

8 0

3 years ago

How are elements arranged in the Periodic Table? A. by their properties B. alphabetically C. by how much they are worth D. in th

algol13

Im on the same test.

5 0

3 years ago

An aqueous solution of ____ will produce a basic solution.

Anastasy [175]

NaClO, K2CO3, and NaF will form basic soltions.

6 0

3 years ago

Read 2 more answers

The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?

Agata [3.3K]

<u>Answer:</u> The molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$PbI_2\rightleftharpoons Pb^{2+}+2I^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Pb^{2+}][I^-]^2$

We are given:

$K_{sp}=7.9\times 10^{-9}$

Putting values in above equation, we get:

$7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L$

Hence, the molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

3 0

3 years ago