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jeka57 [31]
3 years ago
11

Derive the COP of Carnot Refrigerator and Carnot heat Pump.

Engineering
1 answer:
deff fn [24]3 years ago
8 0

Answer:

Answered

Explanation:

COP is the coefficient of performance of refrigerator and Heat pump

COP of refrigerator is given by

cooling effect/work input = \frac{Q_L}{W_{in}}

And for ideal refrigeration cycle

COP= \frac{T_L}{T_H-T_L}

COP of heat pump is given by

Heating effect/ work input = \frac{Q_H}{W_{in}}

And for ideal Heat pump cycle

COP= \frac{T_H}{T_H-T_L}

Now, we can conclude that

COP_{HP}= COP_{R}+1

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Answer to the following question is as follows;

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The amount of alcohol consumption can be influenced by a variety of things, including food.

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Name five or more items that were and may still be made by blacksmith
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When _____ ,the lithium ions are removed from the_____ and added into the _____
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b. Discharging; anode; cathode

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8 0
3 years ago
The hot combustion gases of a furnace are separated from the ambient air and its surroundings, which are at 25 oC, by a brick wa
yanalaym [24]

Answer:

T1 = 625.54 K

Explanation:

We are given;

T_α = Tsur = 25°C = 298K

h = 20 W/m².K,

L = 0.15 m

K = 1.2 W/m.K

ε = 0.8

Ts = T2 = 100°C = 373K

T1 = ?

Assumption:

-Steady- state condition

-One- dimensional conduction

-No uniform heat generation

-Constant properties

From Energy balance equation;

E°in - E°out = 0

Thus,

q"cond – q"conv – q"rad = 0

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴)

Where σ is Stephan-Boltzmann constant and has a value of 5.67 x 10^(-8)

Thus;

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴) = 1.2[(T1 - 373)/0.15] - 20(373 - 298] - 0.8x5.67x10^(-8)[373⁴ - 298⁴] = 0

This gives;

(8T1 - 2984) - (1500) - 520.31 = 0

8T1 = 2984 + 1500 + 520.31

8T1 = 5004.31

T1 = 5004.31/8

T1 = 625.54 K

7 0
2 years ago
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