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Stella [2.4K]
3 years ago
15

What did Zoya and her freind do in response

Chemistry
1 answer:
Mama L [17]3 years ago
5 0
In response of what like what’s the full clear question
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Consider the balanced equation below. 4NH3 + 3O2 2N2 + 6H2O What is the mole ratio of NH3 to N2?
vladimir1956 [14]
Is go be 4x=7 so when you see yo thing pick the 2nd one it's go be b
3 0
3 years ago
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The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate
Karolina [17]

<u>Answer:</u> The value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

<u>Explanation:</u>

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

where,

K_p = equilibrium constant in terms of partial pressure = 3.45

K_c = equilibrium constant in terms of concentration = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 500 K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-1=1

Putting values in above equation, we get:

3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084

The equation used to calculate concentration of a solution is:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}

Initial moles of (CH_3)_3CCl(g) = 1.00 mol

Volume of the flask = 5.00 L

So, \text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M

For the given chemical reaction:

                (CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)

Initial:               0.2                    -                        -

At Eqllm:          0.2 - x               x                       x

The expression of K_c for above reaction follows:

K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}

Putting values in above equation, we get:

0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

[(CH_3)_2C=CH]=x=0.094M

[HCl]=x=0.094M

[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M

Hence, the value of K_p for the reaction is 6.32 and concentrations of (CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl is 0.094 M, 0.094 M and 0.106 M respectively.

8 0
3 years ago
All the nonmetals have some similar physical properties.<br><br> True<br> False
miss Akunina [59]
This is false, all non metals have different physical properties.
4 0
3 years ago
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Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
2 years ago
In water acids form ___.
UkoKoshka [18]

Answer:

Hydrogen ions

Explanation: acids will produce hydrogen ions, I asked my teacher. Please tell me if we are wrong.

6 0
3 years ago
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