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3 years ago

Choose the correct answer from the options given.

Chemistry

1 answer:

Pavel [41]3 years ago

4 0

Answer: 1 part is sulfuric acid is a catalyst

2 part is vanadium (V) oxide is a catalyst

Explanation:

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A tank of oxygen has a volume of 1650 L. The temperature of the gas inside is 35?C. If there are 9750 moles of oxygen in the tan

Paul [167]

Answer:

2192.64 PSI.

Explanation:

From the general law of ideal gases:

PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the container in L (V = 1650 L).

n is the no. of moles of the gas in mol (n = 9750 mol).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature of the gas in (T = 35°C + 273 = 308 K).

∴ P = nRT/V = (9750 mol)(0.082 L.atm/mol.K)(308 K)/(1650 L) = 149.2 atm.

To convert from atm to PSI:

1 atm = 14.696 PSI.

∴ P = 149.2 atm x (14.696 PSI/1.0 atm) = 2192.64 PSI.

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3 years ago

1. inspiration meaning

Furkat [3]

Answer:

inspiration means

the process of being mentally stimulated to do or feel something, especially to do something creative.

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3 years ago

Read 2 more answers

The ability of a material is to transmit flux in an electric field is called____

alukav5142 [94]

The answer is A. Permeability.

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3 years ago

What is the relationship between the following compounds??

34kurt

And what are the compounds?

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4 years ago

For the reaction

s2008m [1.1K]

Answer:

0.558mole of SO₃

Explanation:

Given parameters:

Molar mass of SO₃ = 80.0632g/mol

Mass of S = 17.9g

Molar mass of S = 32.065g/mol

Number of moles of O₂ = 0.157mole

Molar mass of O₂ = 31.9988g/mol

Unknown:

Maximum amount of SO₃

Solution

We need to write the proper reaction equation.

2S + 3O₂ → 2SO₃

We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.

So we simply compare the molar relationship between sulfur and product formed to solve the problem:

First, find the number of moles of Sulfur, S:

Number of moles of S = $\frac{mass }{molar mass}$

Number of moles of S = $\frac{17.9 }{32.065}$ = 0.558mole

Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:

2 mole of Sulfur produced 2 mole of SO₃

Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃

5 0

3 years ago