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mafiozo [28]
4 years ago
12

An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto

rs are perpendicular to the magnetic field. Suppose the magnetic field is strong enough to allow the particles to circle in the field. Note: you'll need to look up the masses for an electron and proton. 1) What is the ratio of the radii of their circular paths rp/re?
Physics
1 answer:
kupik [55]4 years ago
4 0

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

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11Alexandr11 [23.1K]

Answer:

x^2\neq -\frac{5}{13}

First option

Explanation:

<u>Operations with functions </u>

Given two functions f, g, we can perform a number of operations with them including addition, subtraction, product, division, composition, and many others .

We have

f(x)=20x^3-7x^2+3x-7

g(x)=-13x^2-5

We are required to find

\displaystyle \frac{f}{g}(x)

We simply divide f by g as follows

\displaystyle \frac{f}{g}(x)=\frac{20x^3-7x^2+3x-7}{-13x^2-5}

We know rational functions may have problems if the denominator can be zero for some values of x. We must find out if there are such values and exclude them from the domain of the new-found function. We must ensure

-13x^2-5\neq 0

or equivalently

x^2\neq -\frac{5}{13}

Thus the first option is correct

Note: Since x^2 is always a positive number (for x real), our function does not really have any restriction in its domain

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Answer:

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Explanation:

idk

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An object starts at 11 m/s with an acceleration of 12 m/s? What is its velocity after 4.5 seconds?
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Answer:

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Explanation:

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