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mafiozo [28]
3 years ago
12

An electron and a proton have the same kinetic energy upon entering a region of constant magnetic field and their velocity vecto

rs are perpendicular to the magnetic field. Suppose the magnetic field is strong enough to allow the particles to circle in the field. Note: you'll need to look up the masses for an electron and proton. 1) What is the ratio of the radii of their circular paths rp/re?
Physics
1 answer:
kupik [55]3 years ago
4 0

Answer: rp/re= me/mp= 544 * 10^-6.

Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.

Then the dynamic equation for the circular movement is given by:

Fcentripetal= m*ω^2.r

q*v*B=m*ω^2.r

we write this for each particle then we have the following:

q*v*B=me* ω^2*re

q*v*B=mp* ω^2*rp

rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6

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\boxed{\sf Time \ in \ which \ train \ will \ come \ to \ rest = 20 \ sec}

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