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nika2105 [10]
3 years ago
11

A car travels 2.5 hours in a northernly direction for 300 km. determine the cars speed and velocity.

Physics
1 answer:
wolverine [178]3 years ago
5 0

Answer:

Speed= 120 km/h

Velocity= 120 Km/h North

Explanation:

Time= 2.5 hours

Distance= 300 Km

Direction= North

Speed= distance/speed

Velocity= speed and direction

Substituting 300 km for speed and 2.5 hours for time then speed= 300/2.5= 120 km/h

The velocity= 120 km/h North

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xxMikexx [17]

Answer:

Time of race  = 10.18 s

Explanation:

She keeps this acceleration for 17 m and then maintains the velocity for the remainder of the 100-m dash

Time to travel 17 m can be calculated

         s = ut + 0.5at²

         17 = 0 x t + 0.5 x 3.89 x t²

          t = 2.96 s

Velocity after 2.96 seconds

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Remaining distance = 100 - 17 = 83 m

Time required to cover 83 m with a speed of 11.50 m/s

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3 0
3 years ago
A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als
Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

V_T = V_1 + V_2

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

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6 0
2 years ago
The graph below shows the velocity of a car over time.
jekas [21]

Answer:

D. Calculate the area under the graph.

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You can think of such a calculation as determining the area of a rectangle whose sides are velocity and time period. If you make the time period very very small, the rectangle will become a narrow "bar" - a bar with height determined by the average velocity during that corresponding short period of time. The area is, again, the distance made during that time. Now, you can cover the entire area under the curve using such narrow bars. Their areas adds up, approximately, to the total distance made over the entire span of motion. From this you can already see why the answer D is the correct one.

Going even further, one can make the rectangular bars arbitrarily narrow and cover the area under the curve with more and more of these. In fact, in the limit, this is something called a Riemann sum and leads to the definition of the Riemann integral. Using calculus, the area under a curve (hence the distance in this case) can be calculated precisely, under certain existence criteria.

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