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Elza [17]
4 years ago
5

Which statement below correctly describes Earth's gravity?  

Physics
2 answers:
11Alexandr11 [23.1K]4 years ago
7 0
The answer is As objects get closer to Earth, the pull of Earth's gravity increases. -APEX
soldier1979 [14.2K]4 years ago
6 0
I think it is B) the pull of earth's gravity on an object is not affected by the object's distance from Earth.
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Your mass is 65 kg. you stand on a bathroom scale in an elevator on earth. (a) what force would the scale exert when the elevato
erik [133]
I think you would use F = ma
F = 65*10
F = 650N
(The 10m/s is from acceleration due to gravity)
4 0
4 years ago
When you trace the outline of your palm how do you find its area​
oksian1 [2.3K]

Answer:

Explanation:

if its squares count the squares els messure it i think

6 0
3 years ago
Block B has mass 6.00 kg and sits at rest on a horizontal, frictionless surface. Block A has mass 2.50 kg and sits at rest on to
zzz [600]

Answer:

Explanation:

Block A sits on block B and force is applied on block A . Block A will experience two forces 1) force P and 2 )  friction force in opposite direction of motion . Block B will experience one force that is force of friction in the direction of motion .

Let force on block A be P . friction force on it will be equal to kinetic friction, that is μ mg , where μ is coefficient of friction and m is mass of block A

friction force = .4 x 2.5 x 9.8

= 9.8 N

net force on block A = P - 9.8

acceleration = ( P - 9.8 ) / 2.5

force on block B = 9.8

acceleration = force / mass

= 9.8 / 6

for common acceleration

( P - 9.8 ) / 2.5  = 9.8 / 6

( P - 9.8 ) / 2.5 = 1.63333

P = 13.88 N .

4 0
4 years ago
How far will a free falling object fall in 8.7 secs if it started from rest? Remember acceleration is negative for free fall. Do
sleet_krkn [62]

Answer:

h~=371.26m

Explanation:

when an object falls we use the equations of accelerated motion. There is only one that gives distance.

x = ut +  \frac{1}{2} a {t}^{2}

Since we have no initial velocity (started from rest) we can get rid of the (ut) term

where a we substitute g (gravitational acceleration, constant for given heights and almost 9.81m/s^2).

h =  \frac{1}{2} g {t}^{2}  =  \frac{1}{2}  \times 9.81 \times  {8.7}^{2}  = 371.26m

4 0
3 years ago
20 POINTSSS!!!!!!!!
Soloha48 [4]
Answer: A
Hope this help you!!
7 0
3 years ago
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