Answer:don’t mind this I just needed to answer five questions and im not smart
Explanation:
Answer:
Hope it help u plz Brain-list the answer tnx dear
Explanation:
As we know the horizontal component of velocity is
Vx=V *cos(angle)
As given V=25 m/sec
angle=15 degree
hence
Vx= 25* cos(15)
Vx = 25*0.9659
Vx= 24.14 m/sec
Answer:
mr beall will be the one to apply great force to the bags
(a) The frequency of the motion after the collision is 0.71 Hz.
(b) The maximum angular displacement of the motion after the collision is 16.3⁰.
<h3>Speed of the 2.2 kg ball when it collides with 2.7 kg ball</h3>
The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 0.1)
v = 1.4 m/s
<h3>Final speed of both balls after collision</h3>
The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.
Pi = Pf
m₁v₁ + m₂v₂ = vf(m₁ + m₂)
2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)
3.08 = 4.9vf
vf = 3.08/4.9
vf = 0.63 m/s
<h3>Maximum displacement of the balls after the collision</h3>
P.E = K.E
<h3>Maximum angular displacement</h3>
The maximum angular displacement of the balls after the collision is calculated as follows;
<h3>Frequency of the motion</h3>
Learn more about maximum angular displacement here: brainly.com/question/13665036
Answer:0
Explanation:
Given
two particles of mass m and 3m
They move towards each other with velocity v
As the collision is Elastic therefore value of coefficient of restitution is 1
if and are velocity of approach of m and 3 m
and and are velocity after collision respectively
therefore
conserving momentum
Therefore velocity of heavier mass is zero