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Igoryamba
2 years ago
9

A device used to measure the atmospheric pressure is the barometer. true false

Physics
1 answer:
Angelina_Jolie [31]2 years ago
3 0
True, I just learned this a week ago. Is this for Chemistry?
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Why is it good practice for scientists to repeat trails
tensa zangetsu [6.8K]
It makes the data thet they collect more reliable so if they need the data again, they have already tested it a few times so therefor they know that it is right.
8 0
3 years ago
Which perspective is most directly involved with the study of how brain
daser333 [38]

Answer:

biopsychlogy

Explanation:https://www.answers.com/Q/Which_perspective_is_most_directly_involved_with_the_study_of_how_brain_development_might_affect_behavior

6 0
3 years ago
A force of 10 N pressing on an area of 2m2. Calculate the pressure please answer fast it’s a test rn
musickatia [10]

Answer:

pressure=force/area

=10/2

5

Explanation:

3 0
3 years ago
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Doubly ionized lithium Li2+ (Z = 3) and triply ionized beryllium Be3+ (Z = 4) each emit a line spectrum. For a certain series of
EleoNora [17]

Answer:

tex]\lambda_{Be}[/tex] = 22.78 nm

Explanation:

Bohr's model for the hydrogen atom has been used by other atoms with a single electric charge by changing the number of charges by the charge of the new atom (atomic number)

      E_{n}= k e² / 2a₀ (1 /n²)

      ao = h'² / k m e²               h' = h/2πi

For another atom with a single electron in the last layer

      a₀ ’= h’² / k m (Ze)²  

      a₀ ’= a₀ / Z²

Therefore, when replacing in the equation

      E_{n} = - Z²  Eo/n²

     E₀ = 13,606 eV

The transition occurs when the electron stops from one level to another

         E_{n} -  E_{m} = Z² E₀ (1 / n² - 1 / m²) = Z² ΔE

Let's relate this expression to the wavelength

       c = λ f

      E = h f

      E = h c /λ

      h c / λ = Z² ΔE

     λ = 1 / Z² (hc / ΔE)

     λ = 1 / Z² λ_hydrogen

Let's apply this last equation to our case

Lithium Z = 3

     E_{n} = - 9 Eo / n²

     

      40.5 10-9 = 1/9 λ_hydrogen

Beryllium Z = 4

      λ = 1/16 λ_hydrogen

Let's write our two equations is and solve

     40.5 10-9 = 1/9 λ_hydrogen

    tex]\lambda_{Be}[/tex] = 1/ 16 λ_hydrogen

      40.5 10⁻⁹ = 1/9 (16 \lambda_{Be} )

    tex]\lambda_{Be}[/tex] = 40.5 9/16

  tex]\lambda_{Be}[/tex] = 22.78 nm

6 0
3 years ago
Which THREE forms of light are invisible light?
PtichkaEL [24]

Answer:

infrared light

Explanation:

3 0
3 years ago
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