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3 years ago

One way to determine the empirical formula of a compound involves using the percent composition of the compound.

1 answer:

6 0

True! You can use the percentage to determine the amount of moles of each substance in the compound, and then use that information to find the empirical formula.

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How many moles are in 3.0g of A1203?

vfiekz [6]

Answer:

0.065 moles

Explanation:

4 0

3 years ago

Gasoline and kerosene (specific gravity 0.820) are blended to obtain a mixture with a specific gravity of 0.770. Calculate the v

Dmitrij [34]

Answer:

The volumetric ratio is 0,71

Explanation:

Let's begin with the equation:

$Db = Mb/Vb$ (1)

Where:

Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume

And we know: $Vb = Vg + Vk$ (2)

Where:

Vg: Gasoline Volume and Vk: Kerosene Volume

Therefore replacing (2) into (1):

$Db = (Mg + Mk) / (Vg + Vk)$

$Db = (Dg * Vg + Dk * Vk)/(Vg + Vk)$ (3)

Where:

Dg: Gasoline Density and Dk: Kerosene Density

The specific gravity is defined as:

$SG = Substance Density / Reference Density$

Therefore:

$Db = SGb * Dref\\Dg = SGg * Dref\\Dk = SGk * Dref$

Where:

Dref: Reference Density

SGb: Blend Specific Gravity

SGg: Gasoline Specific Gravity (which is 0.7 approximately)

SGk: Kerosene Specific Gravity

Replacing these equations into (3) we get:

$SGb * Dref = (SGg * Dref * Vg + SGk * Dref * Vk)/(Vg + Vk)$

$SGb * Dref = Dref * (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb = (SGg * Vg + SGk * Vk)/(Vg + Vk)$

$SGb * (Vg + Vk) = SGg * Vg + SGk * Vk$

$SGb * Vg + SGb* Vk = SGg * Vg + SGk * Vk$

Replacing with the Specific Gravity data, we obtain:

$0.77 * Vg + 0.77 * Vk = 0.7 * Vg + 0.82 * Vk$

$0.77 * Vg - 0.7 * Vg = 0.82 * Vk - 0.77 * Vk$

$0.07 * Vg = 0.05 * Vk$

$Vg/Vk = 0.05/0.07$

$Vg/Vk = 0.71$

8 0

3 years ago

How many kilograms of a fertilizer are made of pure P2O5 would be required to supply 1.69 kilogram of phosphorus to the soil?

Alekssandra [29.7K]

Answer:

3.89 kg P2O5 must be used to supply 1.69 kg Phosphorus to the soil.

Explanation:

The molecular mass of P2O5 is

P2 = 2* 31 = 62

O5 = 5 *<u> 16 = 80</u>

Molecular Mass = 142

Set up a Proportion

142 grams P2O5 supplies 62 grams of phosphorus

x kg P2O5 supplies 1.69 kg of phosphorus

Though this might be a bit anti intuitive, you don't have to convert the units for this question. The ratio is all that is important.

142/x = 62/1.69 Cross multiply

142 * 1.69 = 62x combine the left

239.98 = 62x Divide by 62

239.98/62 = x

3.89 kg of P2O5 must be used.

3 0

3 years ago

Consider an element Z that has two naturally occuring isotopes with the following percent abundances: the isotope with a mass nu

rodikova [14]

Answer:

Z=22.70

Explanation:

It is given that,

An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.

The average atomic mass for element Z is given by :

$Z=\dfrac{22\times 65+24\times 35}{100}\\\\Z=22.7$

So, the average atomic mass for element Z is 22.70.

3 0

3 years ago

Which statements are true about Figure I and Figure II below? (Check all that apply)

Scilla [17]

Both figures are mixtures,

Figure II is a heterogenous mixture

Figure I is a homogenous mixture

5 0

3 years ago