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aleksklad [387]
3 years ago
8

One way to determine the empirical formula of a compound involves using the percent composition of the compound.

Chemistry
1 answer:
iragen [17]3 years ago
6 0
True! You can use the percentage to determine the amount of moles of each substance in the compound, and then use that information to find the empirical formula.
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Here is a more complex redox reaction involving the dichromate ion in acidic solution: 3N O 2 − + 8H + + C r 2 O 7 2− → 3N O 3 −
Fantom [35]

Answer:

NO2- is the reducing agent.

Cr2O7_2- is the oxidizing agent.

H+ is neither

Explanation:

Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.

Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.

Let us look at the species.

The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.

Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.

Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.

The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.

4 0
3 years ago
Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

Best regards!

4 0
2 years ago
Iron (II) sulfide reacts with hydrochloric acid according to the reaction: FeS(s) + 2 HCl(aq)→ FeCl2(s) + H2S(g) A reaction mixt
RideAnS [48]

The amount ( in moles  of excess  reactant that is left is 0.206 moles


Explanation

FeS(s)  + 2HCl  (aq) →  FeCl2 (s)  + H2S (g)

  • by use of mole ratio of FeS: HCl which is  1:2 this means that  0.223 mole  of FeS  reacted  completely with 0.223   x   2/1 =0.446  moles  0f FeCl2.

  • HCl was in  excess because  0.446 moles of HCl reacted and initially  there was  0.652  moles.
  • Therefore the  amount that was left

      = 0.652- 0.446  =0.206  moles

7 0
3 years ago
Why can't scientists simply use carbon-12 (12C) do determine
Alex

Answer:

carbon-12 is not radioactive

Explanation:

The measurement of the age of dead carbon based life forms requires the use of a radioactive isotope hence it is often referred to as radiocarbon dating.

Carbon-12 and Carbon-14 occur together in living things.The half life of Carbon-14 is about 5670 years.

Hence, since Carbon-12 is not radioactive, it can not be used to measure the age of dead carbon based materials.

8 0
3 years ago
Object is placed on a triple beam balance, and a student moves the sliders until it is balanced with the pointer resting at the
Sveta_85 [38]
The answer is A I hope this helps :)
4 0
3 years ago
Read 2 more answers
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