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Alex Ar [27]
3 years ago
6

Define ΔHrxn and ΔHf . Which Part of the experiment demonstrated the change in enthalpy per mole of a reaction? Which Part of th

e experiment demonstrated the standard molar enthalpy of formation for a reaction?
Chemistry
1 answer:
laila [671]3 years ago
4 0

Answer:

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Explanation:

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Determine the poh of a 0. 188 m nh3 solution at 25°c. the kb of nh3 is 1. 76 × 10-5.
S_A_V [24]

The pOH of the ammonia (NH₃) solution is 2.74.

Calculation:

We will start by composing a balanced ionization of NH₃ in aqueous.

NH₃(aq) + H₂O (l) → NH₄⁺(aq) + OH⁻(aq)

We'll also measure each compound's concentration at the end of the process.

NH₃ will partially dissociate. The quantity of NH3's dissociates can be disregarded. The concentration of NH₃ there at the final reaction is then nearly identical to that at the beginning reaction. NH₃ has a final concentration of 0.188 M.

NH₃≈ 0.188 M

As NH₄⁺ and OH ⁻ have the same ratio, then

[NH₄⁺]= [OH ⁻]

To determine the expression for the concentration of [OH] ions, we shall organize the accordance with the applicable (base constant) for the process into a written form.

Kb = ([NH₄][OH⁻]) / [NH₃]

Hence, the concentration of [NH₄⁺] can be written in the form of [OH⁻].

Kb = ([OH-] [OH⁻]) / [NH₃]

Kb = [OH⁻]² / [NH₃]

[OH⁻]² = Kb *[NH₃]

[OH⁻] = √(Kb *[NH₃])

Next, to find out the OH⁻ concentration we have to express the concentration as a form of the Kb equation :

[OH⁻] = √(1.76 * 10⁻⁵ * 0.188)

[OH⁻] = √3.31 * 10⁻⁶

[OH⁻] = √1.82 * 10⁻³

Hence,

pOH = -log[OH⁻]

pOH = - log1.82 * 10⁻³

pOH = 3 - log1.82

pOH = 2.74

So, the pOH of the NH₃ solution is 2.74.

Learn more about NH₃ here:

brainly.com/question/17021611

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7 0
1 year ago
A chemist mixed two substances together: a blue powder with no smell and a colorless liquid with a strong smell. Their repeating
goblinko [34]

do you know how to give people brainlys

4 0
3 years ago
Need help on this fast ​
soldi70 [24.7K]
Salt is the solute, water is the solvent
3 0
3 years ago
Read 2 more answers
3k+aici3 3kci+ai is what type of reaction
exis [7]
3K      +     AlCl3 -------->  3 KCl     +          Al
element    compound     compound       element

This is single replacement (displacement) reaction.
3 0
3 years ago
H2CO3(aq) + H200 H30 (aq) + HCO3 (aq).
timofeeve [1]

Answer:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

Explanation:

Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:

  • an equilibrium constant is, first of all, a fraction;
  • in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
  • in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
  • each concentration should be raised to the power of the coefficient in the balanced chemical equation;
  • only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.

Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:

K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}

4 0
3 years ago
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