Should be 250m. check with your teacher and let me know
Answer:
1) joule
2) ![kgm^{2}/s^{2}](https://tex.z-dn.net/?f=kgm%5E%7B2%7D%2Fs%5E%7B2%7D)
3) ![10\%](https://tex.z-dn.net/?f=10%5C%25)
Explanation:
1) Luminosity is the <u>amount of light emitted</u> (measured in Joule) by an object in a unit of<u> time</u> (measured in seconds). Hence in SI units luminosity is expressed as joules per second (
), which is equal to Watts (
).
This amount of light emitted is also called radiated electromagnetic power, and when this is measured in relation with time, the result is also called radiant power emitted by a light-emitting object.
Therefore, if we want to calculate luminosity the Joule as a unit will be used.
2) Work
is expressed as force
multiplied by the distane
:
Where force has units of
and distance units of
.
If we input the units we will have:
This is 1Joule (
) in the SI system, which is also equal to ![1 Nm](https://tex.z-dn.net/?f=1%20Nm)
3) The formula to calculate the percent error is:
![\% error=\frac{|V_{exp}-V_{acc}|}{V_{acc}} 100\%](https://tex.z-dn.net/?f=%5C%25%20error%3D%5Cfrac%7B%7CV_%7Bexp%7D-V_%7Bacc%7D%7C%7D%7BV_%7Bacc%7D%7D%20100%5C%25)
Where:
is the experimental value
is the accepted value
![\% error=\frac{|7.34 (10)^{-11} Nm^{2}/kg^{2}-6.67 (10)^{-11} Nm^{2}/kg^{2}|}{6.67 (10)^{-11} Nm^{2}/kg^{2}} 100\%](https://tex.z-dn.net/?f=%5C%25%20error%3D%5Cfrac%7B%7C7.34%20%2810%29%5E%7B-11%7D%20Nm%5E%7B2%7D%2Fkg%5E%7B2%7D-6.67%20%2810%29%5E%7B-11%7D%20Nm%5E%7B2%7D%2Fkg%5E%7B2%7D%7C%7D%7B6.67%20%2810%29%5E%7B-11%7D%20Nm%5E%7B2%7D%2Fkg%5E%7B2%7D%7D%20100%5C%25)
This is the percent error
Answer:
white star
Explanation:
because it is the hottest form of a star
Answer:
The object is moving at constant speed.
Explanation:
The spaces between the dots are equal.
Given :
Mass of water, m = 2 grams.
The temperature of water drops from 31 °C to 29 °C .
The specific heat of water is 4.184 J/(g • °C).
To Find :
Amount of heat lost in this process.
Solution :
We know, heat lost is given by :
![Heat\ lost,H = ms( T_f - T_i)\\\\H = 2\times 4.184 \times ( 31 - 29 )\ J\\\\H = 16.736\ J](https://tex.z-dn.net/?f=Heat%5C%20lost%2CH%20%3D%20ms%28%20T_f%20-%20T_i%29%5C%5C%5C%5CH%20%3D%202%5Ctimes%204.184%20%5Ctimes%20%28%2031%20-%2029%20%29%5C%20J%5C%5C%5C%5CH%20%3D%2016.736%5C%20J)
Therefore, amount of heat lost in this process is 16.736 J.