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crimeas [40]
3 years ago
9

Find the number of moles of in 571,0 g of tetraphosphorous octoxide.

Chemistry
1 answer:
mars1129 [50]3 years ago
3 0

Answer:

Think sorry if i did it wrong The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. Hence 1 mole of He = 4 g of He = 6.022 X 1023atoms of He. 1 g of He = (6.022 X 1023) / 4 atoms of He. 52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He.

For Helium,

Number of atoms=Number of moles ×6.022×1023

No of Moles = 6.022×10

2312.044×10

23 = 2.

Now, atomic mass of He=4

Weight = 2×4 = 8 g

The molar mass that is the mass of 6.022 X 1023 atoms of helium is 4g. Hence 1 mole of He = 4 g of He = 6.022 X 1023atoms of He. 1 g of He = (6.022 X 1023) / 4 atoms of He. 52 g of He = (6.022 X 1023X 52 ) / 4 atoms of He.

As we know, gram atoms = gram mole

here, no of moles = 23/46 =2 so no of gram atoms are 2.

Explanation:

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5. A penny weighs about 2.5 g. How many moles of pennies would be required to equal the mass of the moon (7.3x10^24 kg)
schepotkina [342]

5. 1.16 x 10^{26} moles  moles of pennies would be required to equal the mass of the moon.

6. 12.86 moles of ethanol are in a 750 ml bottle of vodka.

Explanation:

5 .Data given:

mass of penny = 2.5 grams

atomic mass of penny = 62.93 grams/mole

moles present in mass of the moon given as = 7.3 x 10^{24} kg

number of moles = \frac{mass}{atomic mass of  1 mole}

number of moles = \frac{2.5}{62.93}

0.039 moles of penny is present in 2.5 grams

0.039 moles of penny in 2.5 grams of it

so, x moles in 7.3 X 10^{27}  grams

\frac{0.039}{2.5} =\frac{x}{7.3 X 10^{27} }

x = 1.16 x 10^{26} moles

so when the mass of the penny given is equal to the mass of moon, number of moles of penny present is 1.1 x 10^{26} .

6.

Given:

vodka = 40% ethanol

volume of vodka bottle = 750 ml

moles of ethanol =?

density of ethanol =0.79 g/ml

atomic mass of ethanol = 46.07 grams/mole

so, from the density of ethanol given we can calculate how much ethanol is present in the solution.

density = \frac{mass}{volume}

density x volume = mass

0.79 x 750 = 592.5 grams

number of moles = \frac{mass}{atomic mass of 1 mole}

number of moles of ethanol = \frac{592.5}{46.07}

                                               = 12.86 moles of ethanol

6 0
3 years ago
A balloon is filled with 12 L of air at a pressure of 2 atm. What is the volume of the balloon if the pressure is changed to 3 a
mihalych1998 [28]

Answer:

8L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant

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P1 =  2atm, V1 = 12L ,

P2 = 3atm , V2 =

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Divide both sides by 3

V2 = 24 ÷ 3

V2 = 8L

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