<span>The Dynamo Theory
Let Me Know If You Need Anymore Help
~Witt</span>
Answer:Both balls have momentum to start,and they share it after collision
Explanation:both balls have momentum to start and they share it after collision
Answer:
a. 13.7 s b. 6913.5 m
Explanation:
a. How much time before being directly overhead should the box be dropped?
Since the box falls under gravity we use the equation
y = ut - 1/2gt² where y = height of plane above ocean = 919 m, u = initial vertical velocity of airplane = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and t = time it takes the airplane to be directly overhead.
So,
y = ut - 1/2gt²
y = 0 × t - 1/2gt²
y = 0 - 1/2gt²
y = - 1/2gt²
t² = -2y/g
t = √(-2y/g)
So, t = √(-2 × 919 m/-9.8 m/s²)
t = √(-1838 m/-9.8 m/s²)
t = √(187.551 m²/s²)
t = 13.69 s
t ≅ 13.7 s
So, the box should be dropped 13.69 s before being directly overhead.
b. What is the horizontal distance between the plane and the victims when the box is dropped?
The horizontal distance x between plane and victims, x = speed of plane × time it takes for box to drop = 505 m/s × 13.69 s = 6913.45 m ≅ 6913.5 m
Answer:
a)<em> 2000 W/m² </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5
Explanation:
a)
The formula for calculation of total emissive power is:
Total emissive power = E = 
E'<em>λdλ</em>
<em> </em>= 
(0)d<em>λ + </em>
(100)d<em>λ + </em>
(200)d<em>λ + </em>
(100)d<em>λ </em>
(0)d<em>λ</em>
<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>
<em> = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>
<em> = 2000 W/m²</em>
b)
The formula for total intensity of radiation is:
I
= E/π = 200/3.14 = 636.94 W/m<em>².sr </em>
<em>c)</em>
Fo submissive power leaving the surface in range π/4 ≤θ≤π/2
[E(π/4 ≤θ≤π/2)]/E = 
Icosθsinθ dθdΦdλ
where f = infinity, g=2π, h=π/4, i=π/2
By simplifying, we get
= (-1/2)[cos(2π/2)-cos(2π/2)]
= -0.5(-1-0)
=0.5
