Answer:
Correct answer: A.) V = - 16.6 m/s down
Explanation:
Given:
V₀ = 3 m/s initial velocity
t = 2 seconds
g = 9.8 m/s²
V(t) = V(2) = ?
The movement described is a vertical upward shot
For velocity at any time is valid the next formula
V = V₀ - g · t
V = 3 - (9.8 · 2) = 3 - 19.6 = - 16.6 m/s down
Under condition that it has a enough drop height with respect to the ejection point.
God is with you!!!
They’re both describing factors of something
Explanation:
We know that kWh is a commercial unit of energy.
Also, 1 Joule = 1 watt × 1 seconds
Since ,1 h = 3600 s and 1kW = 1000 W
So, the relation is : 
1 watt is defined as the power of an appliance when the energy is transferred at a rate of 1 Joule per second.
Answer:
2.66 m/s² .
Explanation:
Initial velocity , u = 0 m/s
Final Velocity , v = 8 m/s
Time Taken , t = 3 s
So , Acceleration = (v-u)/t = (8 m/s - 0 m/s) /3 sec . = 8/3 m/s² = 2.66 m/s²
