22.0-kg child is riding a playground merry-go-round that is rotating at 40.0 rev/min. What centripetal force is exerted if he is
1 answer:
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Answer:
Explanation:
The gravitational force is an attractive force exerted between any objects with mass.
The magnitude of the gravitational force between two objects is given by:
where
G is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the two objects
In this problem, we have:
is the mass of the 1st ball
is the mass of the 2nd ball
r = 5 m is the separation
So, the gravitational force between them is
Answer:
The horizontal distance is 478.38 m
Solution:
As per the question:
Initial Speed of the bullet in horizontal direction,
Initial vertical velocity of the bullet,
Vertical distance, y = 0.025 m
Now, for the horizontal distance, 'x':
We first calculate time, t:
(since, motion is vertically downwards under the action of 'g')
Now, the horizontal distance, x:
(since, the horizontal acceleration will always be 0)