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arsen [322]
3 years ago
9

use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a vel

ocity of 0.85 m/s. assume the uncertainity in meters in the position of a helium atom if the uncertaunty in the velocity is 0.1 m/s
Chemistry
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

7.7439×10⁻³¹ m

Explanation:

The expression for Heisenberg uncertainty principle is:

\Delta x\times \Delta v=\frac {h}{4\times \pi\times m}

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

\Delta x\times 0.1=\frac {6.62\times 10^{-34}}{4\times \frac {22}{7}\times 0.68\times 10^{-3}}

<u>Δx = 7.7439×10⁻³¹ m</u>

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Answer:

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You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

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