Question

use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a velocity of 0.85 m/s. assume the uncertainity in meters in the position of a helium atom if the uncertaunty in the velocity is 0.1 m/s

Answer 1

Answer:

7.7439×10⁻³¹ m

Explanation:

The expression for Heisenberg uncertainty principle is:

$\Delta x\times \Delta v=\frac {h}{4\times \pi\times m}$

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

$\Delta x\times 0.1=\frac {6.62\times 10^{-34}}{4\times \frac {22}{7}\times 0.68\times 10^{-3}}$

Δx = 7.7439×10⁻³¹ m