Explanation:
Sodium and potassium are in the same group on the periodic table because they both have similar number of valence electrons (1 electron) in their shells
Na = 2,8,1
K = 2,8,8,1
Answer:
Using general gas laws
P1V1/T1 = P2V2/T2
Where P1=380torr = 380mmHg
Vi = 750ml = 0.75dm3
T1= 8c = 281k
P2=0.2torr= 0.2mmHg
T2= 75c = 348k
V2=?
(380*0.75)/281 = (0.2*V2)/348
V2= 1764.77
Explanation:
There are two possible products from this elimination:
-2,3-dimethylbut-1-ene
-2,3-dimethylbut-2-ene
As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.
Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles
