Answer:
(R)-but-3-en-2-ylbenzene
Explanation:
In this reaction, we have a very <u>strong base</u> (<em>sodium ethoxide</em>). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an <u>E2 mechanism</u>, therefore, the hydrogen that is removed must have an <u>angle of 180º</u> with respect to the leaving group (the "OH"). This is known as the <u>anti-periplanar configuration</u>.
The hydrogen that has this configuration is the one that placed with the <u>dashed bond</u> (<em>red hydrogen</em>). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.
See figure 1
I hope it helps!
Answer:
One object has more mass than the other object
Pls mark as brainliest
For this question, suppose the pressure is remained constant, we can use the Charles law to find the answer.
Charles law:
V1/T1 = V2/T2
V1 and T1 are the initial volume and temperature (in K), and V2 and T2 are the final volume and temperature.
We just need to substitute in the numbers in order to find the new volume, V2.
1/5 = V2/10
5V2 = 10
V2 = 2
Therefore, the answer would be 2m3.
If an object is not changing its velocity, then the object is not accelerating. (There’s no acceleration)
Your answer is :
P = K * x where P is partial pressure K is Henry's constant and x is solubility
<span>775 torr = K L·torr/mol * 0.0.0347 mole / liter </span>
<span>K = 775 / 0.0347 = 22334 L·torr/mol </span>
<span>in the second solution we have </span>
<span>1670 = 22334 * x </span>
<span>x = 1670 / 22334 </span>
<span>= 0.075 moles CO2 per liter of water.
</span>
Hope this helps :)
If you need anymore help with questions then feel free to ask me :D
