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Arada [10]
3 years ago
11

What are 2 factors that affect gravitational attraction?

Chemistry
1 answer:
marshall27 [118]3 years ago
3 0
The size of the object and the distance between the objects.
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3: Consider molecules of hydrogen (tiny ones) and oxygen (bigger ones) in a gas mixture. If they have the same average kinetic e
mezya [45]

Answer: Hydrogen molecules will have greatest average speed.

Explanation:

The formula for average speed is  :

\mu_{av}={\sqrt{\frac{8RT}{\pi\times M}}}

R = gas constant  

T = temperature  

M = Molecular Mass

Now putting all the values:

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{8RT}{\pi\times M_{H_2}}}/{\sqrt{\frac{8RT}{\pi\times M_{O_2}}}

\frac{\nu_{H_2}}{\nu_{O_2}}=\sqrt{\frac{16}{2}}

\frac{\nu_{av}_{H_2}}{\nu_{av}_{O_2}}=8

Thus average speed of hydrogen is 8 times the average speed of oxygen. Thus hydrogen molecules will have greatest average speed

8 0
3 years ago
What is this thermodynamic?​
VLD [36.1K]

Answer:

oh coooool

I have one Id it is on ace with maybe 5800 points

maybe this picture will help in something

6 0
2 years ago
How many grams of solute are in 1.00 liter of 0.200m na2so4 solution?
Kisachek [45]
Molarity can be defined as the number of moles of solute in 1 L solution.
Molarity of Na₂SO₄ solution - 0.200 M
this means there are 0.200 moles in 1 L solution 
Molar mass of Na₂SO₄ - 142 g/mol 
therefore mass of Na₂SO₄ in 1.00 L - 0.200 mol x 142 g/mol = 28.4 g
a mass of 28.4 g of Na₂SO₄ is present in 1.00 L
7 0
3 years ago
Mount Everest is 8847 m high.how many centimeters high is Mount Everest?
a_sh-v [17]

Answer: 884,700 cm

Explanation:

Since we already know how high Mount Everest is in meters, we convert it into centimetres.

I hope you found this answer helpful!!

7 0
3 years ago
A first-order decomposition reaction has a rate constant of 0.00440 yr−1. How long does it take for [reactant] to reach 12.5% of
mina [271]

Answer:

473 year

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

To reach 12.5% of reactant means that 0.125 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.125

t = ?

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.125=e^{-0.00440\times t}

t = 473 year

8 0
3 years ago
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