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mrs_skeptik [129]
3 years ago
5

Which element has a larger atomic radius than sulfur?

Chemistry
2 answers:
koban [17]3 years ago
7 0

Answer:

cadmium

Explanation:

Novay_Z [31]3 years ago
6 0

Cadium

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period.

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Which statement is always true of the cathode in an electrochemical cell? Reduction occurs here. It is considered the "negative"
lara31 [8.8K]

Answer:

It Is Considered The "negative" Electrode

Explanation:

An electrochemical cell is an electrolytic cell that drives a non-spontaneous redox reaction through the application of electrical energy. This cell is used to decompose chemical compounds, in a process called electrolysis. An electrode at which reduction take place is called the cathode. In reduction, electrons travel toward the site of reduction such that the negative charge is on the cathode.

7 0
2 years ago
Charlie is balancing an equation. She has identified the atoms and counted the number of each in the reactants and products. Wha
Alecsey [184]
The answer to your question is Coefficients. 

*Hope this helps you! Feel free to message me if you have any further questions. Have a nice day! :)*
8 0
2 years ago
Read 2 more answers
What is the molarity of a solution of 17.0 g of nh4br in enough h2o to make 158 ml of solution? answer in units of m?
vivado [14]
Unit of M is also mole/L, where mole is the moles of solute and L is the volume of the solution.  The latter is given: 158 mL or 0.158 L.  So we need to find out the moles of NH4Br.

Moles of NH4Br = Mass of NH4Br/molar mass of NH4Br = 17.0g/(14+1*4+79.9)g/mol = 0.1736 mole.

So, the molarity of the solution = 0.1736mole/0.158L = 1.10 mole/L = 1.10 M
6 0
3 years ago
A 2.1−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calcula
Fiesta28 [93]

Answer:

Total worth of gold in the ocean = $5,840,000,000,000,000

Explanation:

As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.

Therefore, In 1 L of ocean water there will be,

(4.0 x 10^-10)/0.0021

= 1.9045 x 10^-7 g of gold per Liter of ocean water.

So in 1.5 x 10^-21 L of ocean water, there will be

(1.9045 x 10^-7) * (1.5 x 10^-21)

= 2.857 x 10^14 g of gold in the ocean.

1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is

20.44 * (2.857 x 10^14)

= $5,840,000,000,000,000

8 0
3 years ago
Is Mg a metal non metal or noble gas
madam [21]
It is a metal
hope it helps
8 0
3 years ago
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