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mrs_skeptik [129]
3 years ago
5

Which element has a larger atomic radius than sulfur?

Chemistry
2 answers:
koban [17]3 years ago
7 0

Answer:

cadmium

Explanation:

Novay_Z [31]3 years ago
6 0

Cadium

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period.

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How many unshared electron pairs are present in KrF2
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<span>Kr has 8 valence electrons plus 1 for each Kr-F single bond. Total = 10 elcetrons
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I am 14 and i am in 8th grade, and i really like this boy in my science class, and i really wanna ask him out but i don't know i
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In a calorimeter, 10.0 g of ice melts at 0oC. The enthalpy of fusion of the ice is 334 J/g.
d1i1m1o1n [39]

Answer:

D

Explanation:

In the problem above it is

q = mass x heat fusion

q = 10 g x 334 J/g = 3340 J. Since the ice is absorbing heat it is + 334 J.

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3 years ago
What is the molality of a solution made by dissolving 2 moles of NaOH in 10<br> kg of water?
zaharov [31]

Answer:

0.2mol/kg

Explanation:

molality is the concentration of a solution in moles of solute per kilogram of solvent

moles of solute (NaOH) = 2moles

mass of solvent in kg. =10kg

Therefore molality. = 2moles/10 kg

=0.2mol/kg

5 0
3 years ago
chemist adds of a M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist
Sav [38]

The question is incomplete, here is the complete question:

A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits

<u>Answer:</u> The mass of iron (III) bromide is 246. grams

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Molarity of solution = 2.25 M

Molar mass of iron (III) bromide = 295.6 g/mol

Volume of solution = 370.0 mL

Putting values in above equation, we get:

2.25M=\frac{\text{Mass of solute}\times 1000}{295.6\times 370.0}\\\\\text{Mass of solute}=\frac{2.25\times 295.6\times 370.0}{1000}=246.1g

Hence, the mass of iron (III) bromide is 246. grams

4 0
3 years ago
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