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3 years ago

6

Use the information in the tables to determine whether the solution of the salt formed from the given acid + base combinations w

ill be acidic, basic, or neutral.
HCl + NaOH:
HCl + NH4OH:
CH3COOH + KOH:

2 answers:

Natalija [7]3 years ago

6 0

Answer:

neutral

acidic

basic

Explanation:

Shkiper50 [21]3 years ago

4 0

Answer:

neutral,

acidic,

basic

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What’s plastic.<br> I need this with own words also it has to be half a page

Ket [755]

Answer:

plastic is made up of a wide variety of synthetic materials but use polymers as the main ingredient. Their plasticity makes it easy for plastics to be moulded, extruded or pressed into solid objects of various shapes.

Explanation:

hope this helped :D

3 0

2 years ago

If an equivalent (eq) is defined as a mole of charge, what is the concentration of ca2 in blood plasma in eq if its concentratio

diamong [38]

The concentration of ca 2 in blood plasma in equivalent if its concentration is 0.0080.

Concentration means the amount of or parts in terms of the alternative components. For acid–base reactions, the equivalent weight of an acid or base is the mass which materials or reacts with one mole of hydrogen

In chemistry, equal weight (additionally known as gram equal is the mass of 1 equivalent, that is the mass of a given substance as a way to integrate with or displace a fixed amount of any other substance. The equivalent weight of an detail is the mass which combines with or displaces 1.008 gram of hydrogen or eight. Zero grams of oxygen or 35.five grams of chlorine. those values correspond to the atomic weight divided through the usual valence for oxygen as example that is sixteen.

Charge on one Ca 2+ ion = + 2 .

Concentration of calcium ion = 0.0040M

⇒ Concentration of Ca 2 + in blood plasma = 0.0040 × 2

= 0.0080 equivalent Ca 2 answer

Learn more about concentration here :- brainly.com/question/14469428

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4 0

2 years ago

Which net ionic equation would match this description of a chemical reaction: When a

krok68 [10]

Answer:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

Explanation:

$Mg(NO_{3})_{2}$ , $Na_{3}PO_{4}$ are strong electrolytes. Hence they are fully ionized in aqueous solution.

$Mg_{3}(PO_{4})_{2}$ is a sparingly soluble salt. Hence it remains undissociated in aqueous solution.

So, total ionic equation:

$3Mg^{2+}(aq.)+6NO_{3}^{-}(aq.)+6Na^{+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)+6Na^{+}(aq.)+6NO_{3}^{-}(aq.)$

Net ionic equation is written by omitting spectator ions from total ionic equation.

Here, $Na^{+}$ and $NO_{3}^{-}$ ions are spectator ions as they remain present on both side of total ionic equation.

So, net ionic equation:

$3Mg^{2+}(aq.)+2PO_{4}^{3-}(aq.)\rightarrow Mg_{3}(PO_{4})_{2}(s)$

So, option (d) is correct.

6 0

3 years ago

Liquid 1 has a density of 2.0 g/ml, Liquid 2

Natali5045456 [20]

Liquid 2 because the lower the density the more it floats and the higher the density the more it sinks. The order from top to bottom is liquid 2, liquid 3, liquid 1

8 0

3 years ago

When people smoke, carbon monoxide is released into the air. In a room of volume 70 m3, air containing 5% carbon monoxide is int

KonstantinChe [14]

Answer:

$\frac {dQ}{dt}=0.0001-\frac {Q}{70}\times 0.002$

Explanation:

Given that the volume is $70\ m^3$

The air flows (F) at the rate of $0.002\ m^3/min$ . The concentration of carbon monoxide in the air is 5%.

Let Q be the amount of the carbon monoxide present in the room at time t. then,

$\frac {dQ}{dt}=Rate\ of\ Q_{in}-Rate\ of\ Q_{out}$

Also,

$Rate\ of\ Q_{in}=5\%\ of\ 0.002=0.0001$

$Rate\ of\ Q_{out}=\frac {Q}{70}\times 0.002$

Thus,

$\frac {dQ}{dt}=0.0001-\frac {Q}{70}\times 0.002$

6 0

4 years ago