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xenn [34]
3 years ago
8

What is the pressure of the air in a car tire (in psi) if it is 1.73 atm?

Chemistry
1 answer:
suter [353]3 years ago
6 0

Answer: Thus the pressure of the air in a car tire in psi is 25.4

Explanation:

Pressure is defined as the force exerted per unit area.

Thus units of pressure can be atm or psi or Pa.

Given :

Convert 1.73 atm to psi units

1 atm = 14.7 psi

Thus 1.73 atm = \frac{14.7}{1}\times 1.73=25.4psi

Thus the pressure of the air in a car tire in psi is 25.4

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Explanation:

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Mengapa besi lebih dahulu ditemukan daripada natrium?​
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3 years ago
Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,
7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 )   N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)  ; Kc = 1.54e - 31

2)   N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)  ; Kc = 2.16e - 24

   upon reversing  ( 2 )  equation

     N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)   Kc = 1/2.16e - 24  

    now adding 1 and reversed equation (2)

       N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)

      N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)

   we get ,

                  N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)  Kc = 1.54e-31 × 1/2.61e - 24

       equilibrium constant of equation (3) is -

            Kc = 1.54e - 31 / 2.61e - 24

3 0
3 years ago
Write a word or phrase beginning with each letter of the word gold that described the properties of these gold coins ???? Plzz h
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8 0
4 years ago
Read 2 more answers
The specific heat of a metal is 3.76 cal/g°C. How much heat energy will it take to heat a 25.0 g cylinder of the metal from 21.5
Rudiy27

Answer:

The correct answer is "5217 Cal".

Explanation:

The given values are:

Specific heat,

c = 3.76 cal/g°C

Mass,

m = 25.0 g

Initial temperature,

T₁ = 21.5°C

Final temperature,

T₂ = 77.0°C

Now,

The heat energy will be:

⇒ Q=mc \Delta t

On substituting the given values, we get

⇒     =25.0\times 3.76\times (77-21.5)

⇒     =25\times 3.76\times 55.5

⇒     =5217 \ Cal

4 0
3 years ago
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