Answer:
(a) - 42700 m/s
(b) - 6.8 x 10^-4 m/s^2
Explanation:
initial velocity of star, u = 20.7 km/s
Final velocity of star, v = - 22 km/s
time, t = 1.99 years
Convert velocities into m/s and time into second
So, u = 20700 m / s
v = - 22000 m/s
t = 1.99 x 365.25 x 24 x 3600 = 62799624 second
(a) Change in planet's velocity = final velocity - initial velocity
= - 22000 - 20700 = - 42700 m/s
(b) Accelerate is defined as the rate of change of velocity.
Acceleration = change in velocity / time
= ( - 42700 ) / (62799624) = - 6.8 x 10^-4 m/s^2
Answer:
Approximate height of the building is 23213 meters.
Explanation:
Let the height of the building be represented by h.
0.02 radians = 0.02 × 
= 0.02 x (180/
)
0.02 radians = 1.146°
10.5 km = 10500 m
Applying the trigonometric function, we have;
Tan θ = 
So that,
Tan 1.146° = 
⇒ h = Tan 1.146° x 10500
= 2.21074 x 10500
= 23212.77
h = 23213 m
The approximate height of the building is 23213 m.
Answer:Both are correct
Explanation:
Both are correct because
Mechanical efficiency is the dimensionless term which is the ratio of brake horsepower to the Indicated horse Power
Where brake power is the Power obtained at the crankshaft and
Indicated horsepower is the power obtained in the combustion chamber and this power is the loss in the form of friction.
Volumetric efficiency is the ratio of actual fuel intake to the maximum air fuel that could be taken.
Answer:
The mass of water is 
Explanation:
Given that,
Area of town = 29 km²
Time = 30 min
Height = 2.4 inch
Mass = 103 kg
We know that,
1 m = 39.37 inch
So, 

We need to calculate the volume
Using formula of volume

Put the value into the formula


We need to calculate the mass of water
Using formula of density

Put the value into the formula



Hence, The mass of water is 
Answer:
a) vB = 10.77 ft/s
b) W = 11.30 lb*ft
Explanation:
a) W = 8 lb ⇒ m = W/g = 8 lb/32.2 ft/s² = 0.2484 slug
vA <em>lin</em> = 5 ft/s
rA = 2 ft
v <em>rad</em> = 4 ft/s
vB = ?
rB = 1 ft
W = ?
We can apply The law of conservation of angular momentum
L<em>in</em> = L<em>fin</em>
m*vA*rA = m*vB*rB ⇒ vB = vA*rA / rB
⇒ vB = (5 ft/s)*(2 ft) / (1 ft) = 10 ft/s (tangential speed)
then we get
vB = √(vB tang² + vB rad²) ⇒ vB = √((10 ft/s)² + (4 ft/s)²)
⇒ vB = 10.77 ft/s
b) W = ΔK = K<em>B</em> - K<em>A</em> = 0.5*m*vB² - 0.5*m*vA²
⇒ W = 0.5*m*(vB² - vA²) = 0.5*0.2484 slug*((10.77 ft/s)²-(5 ft/s)²)
⇒ W = 11.30 lb*ft