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Sav [38]
3 years ago
7

The current in the wires of a circuit is 120.0 milliamps.If the voltage impressed across the ends of the circuit where tripled(w

ith no change in its resistance), then its new current would be how amps
Physics
1 answer:
ivanzaharov [21]3 years ago
3 0

Answer:

Explanation:

Current in a wire is 120mA

I = 120mA = 120 × 10^-3 A

I = 0.12 A

If the voltage applied at across the wire is tripled

From ohms law

V=IR

R = V / I

Since R is constant

Then,

V / I = K

Then, we can say

V / I = V' / I'

Given that,

Initially

V = V and I = 120mA

Then, V' = 3V and I' =?

So,

V / I = V' / I'

V / 120 = 3V / I'

Cross multiply

V × I' = 120 × 3V

Divide both sides by V

I' = 120 × 3V / V

I' = 360mA

So, the current in the wire when the voltage was tripled is 360mA, the current was also tripled

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Over a time interval of 1.99 years, the velocity of a planet orbiting a distant star reverses direction, changing from +20.7 km/
madam [21]

Answer:

(a) - 42700 m/s

(b) - 6.8 x 10^-4 m/s^2

Explanation:

initial velocity of star, u = 20.7 km/s

Final velocity of star, v = - 22 km/s

time, t = 1.99 years

Convert velocities into m/s and time into second

So, u = 20700 m / s

v = - 22000 m/s

t = 1.99 x 365.25 x 24 x 3600 = 62799624 second

(a) Change in planet's velocity = final velocity - initial velocity

  = - 22000 - 20700 = - 42700 m/s

(b) Accelerate is defined as the rate of change of velocity.

Acceleration = change in velocity / time

                     = ( - 42700 ) / (62799624) = - 6.8 x 10^-4 m/s^2

8 0
3 years ago
The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
Ksenya-84 [330]

Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

                     = 0.02 x (180/\frac{22}{7})

0.02 radians  = 1.146°

10.5 km = 10500 m

Applying the trigonometric function, we have;

Tan θ = \frac{opposite}{adjacent}

So that,

Tan 1.146° = \frac{h}{10500}

⇒ h = Tan 1.146° x 10500

      = 2.21074 x 10500

      = 23212.77

h = 23213 m

The approximate height of the building is 23213 m.

8 0
2 years ago
Technician A says mechanical efficiency is a comparison between brake horsepower and indicated horsepower. Technician B says vol
Reil [10]

Answer:Both are correct

Explanation:

Both are correct because

Mechanical efficiency is the dimensionless term which is the ratio of brake horsepower to the Indicated horse Power

Where brake power is the Power obtained at the crankshaft  and  

Indicated horsepower is the power obtained in the combustion chamber and this power is the loss in the form of friction.    

Volumetric efficiency is the ratio of actual fuel intake to the maximum air fuel that could be taken.  

8 0
3 years ago
A severe thunderstorm dumped 2.4 in of rain in 30 min on a town of area 29 km2. What mass of water fell on the town? One cubic m
Alexus [3.1K]

Answer:

The mass of water is 1.7661\times10^{9}\ kg

Explanation:

Given that,

Area of town = 29 km²

Time = 30 min

Height = 2.4 inch

Mass = 103 kg

We know that,

1 m = 39.37 inch

So, 2.4\ inch =\dfrac{2.4}{39.37}

2.4\ inch=0.0609\ m

We need to calculate the volume

Using formula of volume

V=H\times A

Put the value into the formula

V=0.0609\times29\times1000^2

V=1766100\ m^3

We need to calculate the mass of water

Using formula of density

\rho=\dfrac{m}{V}

Put the value into the formula

1000=\dfrac{m}{1766100}

m=1000\times1766100

m=1.7661\times10^{9}\ kg

Hence, The mass of water is 1.7661\times10^{9}\ kg

3 0
3 years ago
5–111. A box having a weight of 8 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA)1 = 5 ft>s while co
Elis [28]

Answer:

a) vB = 10.77 ft/s

b) W = 11.30 lb*ft

Explanation:

a) W = 8 lb   ⇒  m = W/g = 8 lb/32.2 ft/s² = 0.2484 slug

vA <em>lin</em> = 5 ft/s

rA = 2 ft

v <em>rad</em> = 4 ft/s

vB = ?

rB = 1 ft

W = ?

We can apply The law of conservation of angular momentum

L<em>in</em> = L<em>fin</em>

m*vA*rA =  m*vB*rB    ⇒    vB = vA*rA / rB

⇒   vB = (5 ft/s)*(2 ft) / (1 ft) = 10 ft/s  (tangential speed)

then we get

vB = √(vB tang² + vB rad²)   ⇒   vB = √((10 ft/s)² + (4 ft/s)²)

⇒   vB = 10.77 ft/s

b) W = ΔK = K<em>B</em> - K<em>A</em> = 0.5*m*vB² - 0.5*m*vA²

⇒     W = 0.5*m*(vB² - vA²) = 0.5*0.2484 slug*((10.77 ft/s)²-(5 ft/s)²)

⇒     W = 11.30 lb*ft

6 0
3 years ago
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