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babymother [125]
3 years ago
12

Can someone help me?!!!!!

Physics
1 answer:
kramer3 years ago
5 0

Answer:

Parabola

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal (x) direction, with constant velocity v_x. In fact, there are no forces acting along this direction (if we neglect air resistance), so the acceleration is zero and the velocity is constant

- An uniformly accelerated motion along the vertical (y) direction, with constant acceleration g=9.8 m/s^2 downward (acceleration due to gravity). This acceleration is due to the force of gravity that pulls the projectile downward.

The composition of these two motions gives a parabolic trajectory. In fact, the equations of the motion along the two directions are:

x(t) = v_x t (1)

y(t) = h + v_y t - \frac{1}{2}gt^2 (2)

Solving for t in eq.(1),

t=\frac{x}{v_x}

and substituting into (2)

y(t) = h + \frac{v_y}{v_x}x - \frac{1}{2}g(\frac{x}{v_x})^2

which is the equation of a parabola.

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A tall tube is evacuated and its stopcock is closed. The open end of the tube is immersed in a container of water (density 10^3
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Answer:

10.19 m

Explanation:

Water will rise to equalize the pressure inside and outside the tube.

The equation of pressure is given by

p=\rho gh

Where,

p = Pressure of air = 10⁵ N/m²

ρ = Density of water = 10³ kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Height the water will rise

h=\frac{p}{gh}\\\Rightarrow h=\frac{10^5}{9.81\times 10^3}\\\Rightarrow h=10.19\ m

∴ The water will rise by 10.19 m.

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