To solve this problem we must first find the potential on the body which is given as a product between the number of turns, the area and the variation of the magnetic field as a function of time. Once the potential is found, we will apply Ohm's Law with which we can find the induced current on the body. Our values are,
a) The magnitude of average induced emf is given by
Here N =1
b) The magnitude of the induced current is
Here Resistance is
Therefore the induced current is 0.00108A
The list of choices you gave us doesn't have any true statements on it.
Answer:
Explanation:
In space station artificial gravity is created by rotational motion of space station
Centifugal acceleration creates artificial gravity
ω²r = g
ω² x 400 = 9.8
ω² = 9.8 /400
ω = .1565 rad /s
no of turns per min ω / 2π per sec = 1.56 rev per min .
For Mars
Same theory will apply
ω²r = g
ω² x 400 = 3.7
ω² = 3.7 /400
ω = . 096 rad /s
n = ω / 2π
= .096 / 2π
=.01528 per sec
per min
= .9168 per min .
Answer:0.10283 J
Explanation:
Given
mass of block(m)=0.0475 kg
radius of track (r)=0.425 m
when the Block is at Bottom Normal has a magnitude of 3.95 N
Force acting on block at bottom
u=5.583 m/s
At top point
v=3.188 m/s
Using Energy conservation
i.e. 0.10283 J of energy is wasted while moving up.
That gives you the magnitude of velocity, but it doesn't handle
the directions that are involved.