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4 years ago

15

Which statement is correct about y = cos^–1 x?

1 answer:

Maurinko [17]4 years ago

5 0

Answer:

A) If the domain of y=cos(x) is restricted to [0, π], y=cos^-1(x) is a function.

Step-by-step explanation:

In order for the inverse function to be a function, the original must pass the horizontal line test: a horizontal line must intersect the function in only one place.

As you can see from the attached graph, restricting the cosine function to the domain [0, π] allows it to pass the horizontal line test, so its inverse will be a function.

__

Restricting the domain to [-π/2, π/2] does not limit cos(x) to something that will pass the horizontal line test.

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A warehouse distributor of carpet keeps 6,000 yards of deluxe shag carpet in stock during a month. The average demand for carpet

Bond [772]

Answer:

The probability that a customer’s order will not be met during a month is 1.67.

Step-by-step explanation:

Given : A warehouse distributor of carpet keeps 6,000 yards of deluxe shag carpet in stock during a month. The average demand for carpet from the stores that purchase from the distributor is 4,500 yards per month, with a standard deviation of 900 yards.

To find : What is the probability that a customer’s order will not be met during a month?

Solution :

Average Mean $\mu=4500$

Sample Mean $x=6000$

Standard deviation $\sigma=900$

The formula is given by,

$Z=\frac{x-\mu}{\sigma}$

Substitute the value in the formula,

$Z=\frac{6000-4500}{900}$

$Z=\frac{1500}{900}$

$Z=1.67$

The probability that a customer’s order will not be met during a month is 1.67.

7 0

3 years ago

Marianna [84]

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Step-by-step explanation:

Let us revise some logarithmic rules

$log(a)^{n}=nlog(a)$
$log(ab)=log(a)+log(b)$
$nlog(a)+mlog(b)=log[(a)^{n}][(b)^{m}]$

∵ 10 log(x) + 5 log(64)

- At first re-write 10 log(x)

∴ 10 log(x) = $log(x)^{10}$

- Then re-write 5 log(64)

∴ 5 log(64) = $log(64)^{5}$

∴ 10 log(x) + 5 log(64) = $log(x)^{10}$ + $log(64)^{5}$

- Use the 3rd rule above to make it single logarithm

∵ $log(x)^{10}$ + $log(64)^{5}$ = $log[(x)^{10}][(64)^{5}]$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(64)^{5}]$

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

∴ We can write 64 as $2^{6}$

∴ $(64)^{5}=(2^{6})^{5}$

- Multiply the two powers of 2

∴ $(64)^{5}=(2)^{30}$

∴ 10 log(x) + 5 log(64) = $log[(x)^{10}][(2)^{30}]$

The expression into a single logarithm is $log[(x)^{10}][(2)^{30}]$

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

6 0

3 years ago

The greatest distance across the

FromTheMoon [43]

Answer:

1 quintillion km

Step-by-step explanation:

do you know that you can put 100000 earths to sun to fill it

6 0

3 years ago

How do you do decrease 280 by 95%

stealth61 [152]

95% = 0.95

280 - (280 * 0.95)

7 0

3 years ago

8ax-6x-12a+9 what is the value?

Nuetrik [128]

Answer:

−10a+9

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers