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ivann1987 [24]
3 years ago
14

54 km/h is equal to

Physics
1 answer:
pogonyaev3 years ago
7 0

\Huge{\underline{\underline{\mathfrak{\green{AnsWeR:}}}}}

1 km/h = 5/18 m/s

54 km/h = 54×5/18 m/s

<h2>= 15 m/s</h2>
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what features of stars are plotted on the Hertzsprung-Russell diagram? density and mass B. physical structure and composition ap
aliina [53]

Answer:

its luminosity (brightness) and temperature

Explanation:

3 0
3 years ago
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A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt
GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

  Weight of sculpture - Weight of water displaced = 13.86 N

  15.76 - Weight of water displaced = 13.86

   Weight of water displaced = 1.9 N

   Mass of water displaced = 0.194 kg

 Mass = Volume x Density

  0.194 = V x 1000

  Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity =  Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0
3 years ago
Quantum mechanics applies to A) subatomic, atomic, nanometer-size, and micrometer-size systems. B) nanometer, micrometer, and ki
Leto [7]

Answer: D) subatomic, atomic, and nanometer-size systems.

Explanation: Quantum mechanics applies to subatomic, atomic, and nanometer-size systems.

8 0
3 years ago
If two coils placed next to one another have a mutual inductance of 3.00 mH, what voltage (in V) is induced in one when the 2.50
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Answer:

-0.1875 V.

Explanation:

Using

E₂ = MdI₁/dt........................ Equation 1

Where E₂ = Voltage induced in the second coil, M = mutual inductance of both coil, dI₁ = change in current in the first coil, dt = change in time.

Given: M = 3.00 mH = 0.003 H, dI₁ = (0-2.50) = -2.5 A, dt = 40 ms = 0.04 s.

Substitute into equation 1

E₂ = 0.003(-2.5)/0.04

E₂ = -0.1875 V.

Hence the induced emf = -0.1875 V.

3 0
3 years ago
A railroad car with a mass of 30,000 kg is moving at 2.0 m/s when it runs into an at-rest freight car with an equal mass. The ca
11Alexandr11 [23.1K]
The total momentum of the system is preserved through the collision.

Note that momentum is
P = m*v
where m = mass
v = velocity.

Initial momentum:
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P2 = 0 for the starionary car.

Final momentum:
P3 = (30000 + 30000)*v = 60000v (kg-m)/s

Because momentum is preserved,
P3 = P1 + P2
60000v = 60000
v = 1 m/s
The final velocity is 1 m/s.

Answer: 1.0 m/s
4 0
3 years ago
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