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Answer:
d = 2083.33 m
Explanation:
Given that,
Acceleration of the train, a = 0.15 m/s²
The initial speed of the car, u = 0\
Final velocity, v = 25 m/s
We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :
So, the minimum distance is 2083.33 m