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3 years ago

1+1is= Make that as a ?

Chemistry

1 answer:

VladimirAG [237]3 years ago

5 0

<u>Answer:</u> The correct answer to this problem is 2.

<u>Explanation:</u>

We are given a mathematical problem, which is:

1 + 1 = ?

To solve this, we use the mathematical operator known as addition. In this, we add two numbers and the resulting value is the answer to the problem.

By adding 1 and 1, we get:

$\Rightarrow 1+1=2$

Thus, the correct answer to this problem is 2.

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My answer was 10 and it’s telling me it’s wrong..what did i do wrong?

Keith_Richards [23]

Answer:

1.586x10^-9

Explanation:

To make a multiplication in scientific notation we need to multiply the coefficients and sum the exponents:

Coefficients: 2.600 * 6.1000 = 15.86

Exponents: -5 + (-5) = -10

The result is:

15.86x10^-10

As the scientific notation must be given with only 1 number in the left of the point:

5 0

3 years ago

Which of the following is NOT a true statement?

Artyom0805 [142]

Answer:

c is not a true statement

8 0

3 years ago

Read 2 more answers

You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?

zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

H = 1g

O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

Mass of O in glucose = $\frac{6x16}{180}$ x 55

= $\frac{96}{180}$ x 55

= 0.53 x 55

Mass of oxygen in glucose = 29.3g

8 0

3 years ago

The molar mass of sucrose (C12H22O11) is 342.3 g/mol. A chemist has a 0.500-mol sample of sucrose. What is the mass, in grams, o

Gekata [30.6K]

171 is the answer that I got after my calculations.

8 0

3 years ago

Read 2 more answers

A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3

IRINA_888 [86]

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram