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Montano1993 [528]
3 years ago
12

Gravitational force is reduced by _____ between objects.

Physics
2 answers:
Fittoniya [83]3 years ago
8 0
Gravitational force is reduced by:
B. The square of the distance..... hope that helps ;)
Anon25 [30]3 years ago
8 0

Answer : The correct option is, (B) the square of the distance

Explanation :

Gravitational force : It is defined as the gravitational force is directly proportional to the product of the masses of the two object and an inversely proportional to the square of the distance between the two object.

The gravitational force (F) between the two object masses (M) and (m) and the distance between the two object (r) is given by the equation,

F=G\frac{Mm}{r^2}

where,

G = gravitational constant

When the distance between the two object doubles then the gravitational force is reduced by one fourth (1/4)th between objects.

When the distance between the two object triples then the gravitational force is reduced by one ninth (1/9)th between objects.

Gravitational force is inversely proportional to the square of the distance of two object.

Therefore, the gravitational force is reduced by the square of the distance between objects.

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Sort the units based on the measurement system they're used in
timurjin [86]

Answer:

Kelvin

Explanation:

fact as per the guideline given

7 0
3 years ago
Conservation of Momentum<br> No one likes you little trolls please send an actual answer
Olin [163]

Hello!

This is an example of an inelastic collision, where the two objects "stick" to each other after their collision. (The Goalkeeper CATCHES the puck).

We can write out the conservation of momentum formula:

m1vi + m2vi = m1vf + m2vf

Let:

m1 = mass of puck

m2 = mass of the goalkeeper

We know that the initial velocity of the goalkeeper is 0, so:

m1vi + m2(0) = m1vf + m2vf

m1vi = m1vf + m2vf

The final velocities will be the same, so:

m1vi = (m1 + m2)vf

Plug in the given values:

(0.16)(40)/ (0.16 + 120) = vf ≈ 0.0533 m/s

Using the equation for momentum:

p = mv

The object with the LARGER mass will have the greater momentum. Thus, the Goalkeeper has the largest momentum as p = mv; a greater mass correlates to a greater momentum since the velocity is the same between the two objects. The puck would have a momentum of p = (.16)(0.0533) = 0.008528 kgm/s, whereas the goalkeeper would have a momentum of

p =  (120)(0.0533) = 6.396 kgm/s.

3 0
2 years ago
you push a block of 50kg with a force of 400 N over a distance of 8m. How much kinetic energy does the box gain?
MatroZZZ [7]

Answer:

160000

Explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
4 0
2 years ago
A car is driven 13 mi east and then certain distance due north, ending up at the position 25 degrees north of east of its initia
Kobotan [32]

Answer: Hello mate!

lets define the north as the y-axis and east as the x-axis.

Using the notation (x,y) we can define the initial position of the car as (0,0)

then the car travells 13 mi east, so now the position is (13,0)

then the car travels Y miles to the north, so the position now is (13, Y)

and we know that the final position is 25° degrees north of east of the initial position. This angle says that the distance traveled to the north is less than 13 mi because this angle is closer to the x-axis (or east in this case).

This angle is measured from east to north, then the adjacent cathetus is on the x-axis, in this case, 13mi

And we want to find the distance Y, so we can use the tangent:

Tan(25°) = Y/13  

tan(25°)*13 mi = Y = 6.06 mi.

3 0
3 years ago
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ
kherson [118]

Answer: 5 units

Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:

The trajectory is the path followed by the body (is a scalar magnitude).

The <u>displacement</u> is the distance in a straight line between the initial and final position (is a vector magnitude).

According to this, in the description of the object (figure attached) placed at 0 on a number line and moving some units to the left and some oter units to the right, we are talking about the path followed by the object, hence its trajectory. So, 13 units is its trajectory.

But, if we talk about displacement, we have to draw a straight line between the initial position of the object (point 0) to its final position (point 5).

Now, being this an unidimensional problem, the displacement vector for this object is 5 units.

8 0
3 years ago
Read 2 more answers
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