Question

A total charge of 6.3×10?8 C is distributed uniformly throughout a 2.7-cm radius sphere. The volume charge density is:

Answer 1

Answer:

$7.6\cdot 10^{-4} C/m^3$

Explanation:

The volume charge density is given by:

$\rho = \frac{q}{V}$

where

q is the charge

V is the volume of the sphere

In this problem, we have:

$q=6.3\cdot 10^{-8} C$ is the charge

$r=2.7 cm=0.027 m$ is the radius of the sphere, so its volume is

$V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (0.027 m)^3=8.24\cdot 10^{-5} m^3$

So, the volume charge density is

$\rho = \frac{6.3\cdot 10^{-8} C}{8.24\cdot 10^{-5} m^3}=7.6\cdot 10^{-4} C/m^3$