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solmaris [256]
3 years ago
11

What are the molarity and the normality of a solution made

Chemistry
1 answer:
Nikitich [7]3 years ago
3 0

Explanation:

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

Hence, calculate the molarity of given solution as follows.

     Molarity of citric acid = \frac{\text{mass of citric acid}}{\text{molar mass of citric acid}} \times \frac{1}{\text{volume of solution(L)}}

                                 = \frac{25 g}{192.13 g/mol} \times \frac{1}{0.75 L}

                                 = 0.173 M

As citric acid is a triprotic acid so, upon dissociation it gives three hydrogen ions.

          Normality = Molarity × no. of hydrogen or hydroxide ions

                            = 0.173 × 3

                            = 0.519 N

Thus, we can conclude that molarity of given solution is 0.173 and its normality is 0.519 N.

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For the following reaction, 22.0 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas . nitrogen mono
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<h3>What is a limiting reagent?</h3>

The reactant that is entirely used up in a reaction is called as limiting reagent.

The reaction:

2NO(g) +2H_2(g) → N_2 +2H_2O

Moles of nitrogen monoxide

Molecular weight: M_(_N_O_)=30g/mol

n_(_N_O_) =\frac{mass}{molar \;mass}

n_(_N_O_) =\frac{22.0}{30g/mol}

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Moles of hydrogen

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Hydrogen gas is in excess.

NO is the limiting reagent.

The amount of the excess reagent remains after the reaction is complete.

n_(_N_2_) = (2.9 mol- 0.73 mol NO x \frac{1 \;mol \;of \;H_2}{2 \;mole \;of \;NO}) x \frac{2g \;of \;H_2}{mole \;of \;H_2}

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Learn more about limiting reagents here:

brainly.com/question/26905271

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