Answer:
30.22°.
Explanation:
Given that
height of the bridge ,h= 12 ft
The distance of the lake from bridge ,L= 7 m
Lets take angle = θ
Now by using diagram
We can say that
That is why the angle will be 30.22°.
Calculate the speed of a satellite moving in a stable circular orbit about the Earth at a height of 3600 km.
1 answer:
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The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.
The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.
The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.Let the common acceleration = a m/s^2
Man: <em>net force = T - f = m a = 50 a </em>
<em>net force = T - f = m a = 50 a </em>
<em>Plank: net force = T + f = m a = 100 a</em>
<em>net force = T - f = m a = 50 a </em>
<em>Plank: net force = T + f = m a = 100 a</em>
<em>As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons. </em>
[correct me if I'm wrong]:)
