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2 years ago

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A 11,000-kg train car moving due east at 21.0 m/s collides with and couples to a 23,000-kg train car that is initially at rest.

What is the common velocty of the two-car train after the collisions?

1 answer:

Tomtit [17]2 years ago

6 0

Answer:

v = 6.79 m/s

Explanation:

It is given that,

Mass of a train car, m₁ = 11000 kg

Speed of train car, u₁ = 21 m/s

Mass of other train car, m₂ = 23000 kg

Initially, the other train car is at rest, u₂ = 0

It is a case based on inelastic collision as both car couples each other after the collision. The law of conservation of momentum satisied here. So,

$m_1u_1+m_2u_2=(m_1+m_2)V$

V is the common velocity after the collisions

$V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{11000\times 21}{(11000+23000)}\\\\V=6.79\ m/s$

So, the two car train will move with a common velocity of 6.79 m/s.

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Learn more about the apparent weight of the body in a lift here:

brainly.com/question/28045397

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