An spring has a period of 4 seconds. What is its frequency?

A rock is thrown downward from an unknown height above the ground with an initial speed of 6.1 m/s. It strikes the ground 1.7 s

insens350 [35]

Answer:

24.531 m

Explanation:

t = Time taken = 1.7 s

u = Initial velocity = 6.1 m/s

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=6.1\times 1.7+\dfrac{1}{2}\times 9.8\times 1.7^2\\\Rightarrow s=24.531\ m$

The initial height of the rock above the ground is 24.531 m

7 0

3 years ago

Anyone know how to do this?

MrMuchimi

The voltage from one side of the battery all the way around to the other side of the battery is 12v .

If 4 of those volts show up across the circle-thing, then the rest of the 12v ... 8v ... Must show up across the set of parallel rectangles.

To get that answer, I subtracted the 4 from the 12.

Just like it says in choice-C.

7 0

2 years ago

Adhesion is when forces of the molecules are more strongly drawn to each other than the molecules in other substances true or fa

SSSSS [86.1K]

Answer:

False

Explanation:

that is cohesion. adhesion is force between dissimilar molecules of a body

6 0

3 years ago

A person walks due south from point A for 500 yards and then due west for 300 yards, arriving at point B. Answer the following q

Pepsi [2]

The total displacement of the person walking from point A to point B is 300 yards.

As shown in the figure we can conclude that the required method to calculate the total displacement is the Pythagoras theorem.

<h3>Pythagoras theorem in brief :</h3>

According to the Pythagorean Theorem, the square that represents the hypotenuse, or side of a right triangle that faces the right angle, is equal to the total of the squares on the triangle's legs.(or, in popular algebraic notation, $a^2 + b^2 = c^2$ ).

<h3>Calculation: </h3>

Let,

a = 500

b= 300

Hence by using Pythagoras' theorem

Total displacement of the person = $\sqrt{500^{2} + 300^{2} }$ = $\sqrt{900000}$ = $300$

Thus the total displacement of the person from starting point is 300 yards.

Learn more about the displacement examples here:

brainly.com/question/11188852

#SPJ4

5 0

2 years ago

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 41m in front of you. Your reaction time

nordsb [41]

Answer:

Maximum speed you could have and still not hit the deer = 24.07 m/s

Explanation:

Let the maximum speed you could have and still not hit the deer be y.

Your reaction time before stepping on the brakes is 0.50s.

Distance traveled during this time = 0.5y

A deer steps onto the road 41m in front of you

Remaining distance to deer = 41 - 0.5y

The maximum deceleration of your car is 10 m/s²

We have equation of motion, v² = u² + 2as

Initial velocity, u = y m/s

Final velocity, v = 0 m/s

Acceleration, a = -10 m/s²

Displacement, s = 41 - 0.5y

Substituting,

v² = u² + 2as

0² = y² + 2 x -10 x (41 - 0.5y)

20(41 - 0.5y) = y²

820 - 10 y = y²

y² + 10 y -820 = 0

y = 24.07 m/s or y = -34.06 m/s(not possible)

Maximum speed you could have and still not hit the deer = 24.07 m/s

7 0

3 years ago