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3 years ago

An spring has a period of 4 seconds. What is its frequency?

Physics

1 answer:

trasher [3.6K]3 years ago

7 0

Answer:

2Hz

Explanation:

Hope this helps

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develop a plan to test the hardness of a sample of feldspar using the following items glass plate copper penny and streak plate

Artemon [7]

Stroke then 3883 you choke <3333333333

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2 years ago

A radio station's channel, such as 100.7 fm or 92.3 fm, is actually its frequency in megahertz (mhz), where 1mhz=106 hz and 1hz=

AURORKA [14]

The frequency of the radio station is
$f=88.7 fm= 88.7 MHz = 88.7 \cdot 10^6 Hz$

For radio waves (which are electromagnetic waves), the relationship between frequency f and wavelength $\lambda$ is
$\lambda= \frac{c}{f}$
where c is the speed of light. Substituting the frequency of the radio station, we find the wavelength:
$\lambda= \frac{3 \cdot 10^8 m/s}{88.7 \cdot 10^6 Hz}=3.38 m$

6 0

3 years ago

Read 2 more answers

A 40kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hill side?

bagirrra123 [75]

Answer:

Explanation:

The height of the hill side can be found by using the formula

$h = \frac{p}{m} \\$

p is the potential energy

m is the mass

From the question we have

$h = \frac{1568}{40} = \frac{196}{5} \\$

We have the final answer as

Hope this helps you

5 0

2 years ago

Read 2 more answers

The smallest separation resolvable by a microscope is of the order of magnitude of the wavelength used. What energy electrons wo

hjlf

Answer: a) for 150 Angstroms 6.63 *10^-3 eV; b) for 5 Angstroms 6.02 eV

Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

Finally we have:

eΔV=p^2/2m= h^2/(2*m*λ^2)

replacing we obtained the above values.

6 0

2 years ago

2. A car accelerates uniformly from +10.0 m/s to +50.0 m/s over a distance of 225 m. How long did it take to go that distance? S

artcher [175]

Let's call the constant acceleration a.
At a time t, its speed will thus be v(t)=a*t+v0 where v0 is its initial speed, here 10 m/s. Hence v(t)=a*t+10.

From there we can deduce the position P(t)=a*t^2/2+10t+p0 where p0 is the initial position, here 0.

Hence P(t)=a*t^2/2+10t

Let's call T the time at which it's at 50 m/s, we know that P(T)=225m and that v(T)=50 m/s hence a*T+10=50 thus a=40/T and P(T)=(40/2+10)T=30T

Hence T=225/30=7.5

It took 7.5 seconds

7 0

2 years ago