Ask question

Ask question

All categories

3 years ago

15

What is the total of a 10 ohm, 20 ohm, and 200 ohms resistors connected in a parallel

1 answer:

Feliz [49]3 years ago

4 0

Answer:

Answer is 6.452Ω

Explanation:

R1= 10Ω

R2= 20Ω

R3= 200Ω

1/R123= 1/R1+ 1/R2+ 1/R3

Find the LCM then find the inverse of the answer, then replace the values of the lettered resistors.

I hope this helps if not please let me know

You might be interested in

The narrator of a story

34kurt

The answer is d! I’m happy to help :)

7 0

3 years ago

Read 2 more answers

Gymnastics has great benefits for you both your body and mind? True False

Alenkasestr [34]

Answer:

I think the answer is True

6 0

3 years ago

Read 2 more answers

How wood helps in home insulation plz answer fast<br>plz answwweeeeeeerrrrrrr

Usimov [2.4K]

Wood is a poor conductor and therefore a good insulator keeping heat inside

3 0

3 years ago

Read 2 more answers

Which law describes how the Earth applies a gravitational force on the Moon, the Moon applies a gravitational force on Earth? *

nikdorinn [45]

The answer is Newton's 3rd Law. The reason why is because a force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject ofNewton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

3 0

3 years ago

Read 2 more answers

The California sea lion is capable of making extremely fast, tight turns while swimming underwater. In one study, scientists obs

anygoal [31]

Answer:

Acceleration of Sea Lion is 4.41 g

This is 49% of maximum jet acceleration given as a = 9g

Explanation:

As we know that the radius of the circular loop is given as

R = 0.37 m

The speed of the fish is given as

$v = 4 m/s$

Now the centripetal acceleration of the sea lion is given as

$a_c = \frac{v^2}{R}$

$a_c = \frac{4^2}{0.37}$

$a_c = 43.2 m/s^2$

as we know that

$g = 9.8 m/s^2$

so we have

$a = 4.41 g$

Now Percentage of this acceleration wrt maximum jet acceleration is given as

$P = \frac{4.41 g}{9g} \times 100$

$P = 49$ %

6 0

3 years ago