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Fudgin [204]
2 years ago
15

What is the total of a 10 ohm, 20 ohm, and 200 ohms resistors connected in a parallel

Physics
1 answer:
Feliz [49]2 years ago
4 0

Answer:

Answer is 6.452Ω

Explanation:

R1= 10Ω

R2= 20Ω

R3= 200Ω

1/R123= 1/R1+ 1/R2+ 1/R3

Find the LCM then find the inverse of the answer, then replace the values of the lettered resistors.

I hope this helps if not please let me know

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suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
ehidna [41]
Use the Inverse square law, Intensity (I)<span> of a light </span>is inversely proportional to the square of the distance(d).

I=1/(d*d)

Let Intensity for lamp 1 is L1 distance be D1 so on, L2 D2 for Intensity for lamp 2 and its distance.

L1/L2=(D2*D2)/(D1*D1)

L1/15=(200*200)/(400*400)
L1=15*0.25
L1=3.75 <span>candela</span>
3 0
2 years ago
Can someone pls help me
natali 33 [55]

Answer:

if not mistaken its b

5 0
2 years ago
Read 2 more answers
The maximum current output of a 60 ω circuit is 11 A. What is the rms voltage of the circuit?
bezimeni [28]

Answer:

660V

Explanation:

V=IR

V=11×60

=660V

hope this helps

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8 0
3 years ago
A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec
Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude 'q' enters into a magnetic field such that its velocity vector '\vec{V}' is perpendicular to the direction of the magnetic field '\vec{B}', then it will experience a force, called Lorentz force (\vec{F_{L}}), given by

\vec{F_{L}} = \vec{V} \times \vec{B}

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force (F_{L}) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.

7 0
3 years ago
An electric field of 2.09 kV/m and a magnetic field of 0.358 T act on a moving electron to produce no net force. If the fields a
My name is Ann [436]

Answer:

The velocity is  v =  5838 \ m/s

Explanation:

From the question we are told that

   The electric field is E  =  2.09 kV/m =  2.09 *10^{3} \ V/m

    The magnetic field is  B  =  0.358 \ T

     

Generally the force experienced by the electron due to the magnetic field is

         F_m  =  qvB

Generally the force experienced by the electron due to the electric  field is

       F_e =  qE

Since from the question the net force is zero  then

     F_e =  F_m

=>    v =  \frac{E}{B}

Substituting values

      v =  \frac{2.09*10^{3}}{0.358 }

    v =  5838 \ m/s

     

8 0
2 years ago
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