How many sodium ions are in the initial 50.00-mL solution of Na2CO3

1 answer:

8 0

From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.

Na2CO3 = 2Na+ + CO3^2-

7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present

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Ostrovityanka [42]

Answer:

<h3>The answer is 11.88 moles</h3>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{7.15 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 11.87707641...$

We have the final answer as

<h3>11.88 moles</h3>

Hope this helps you

4 0

3 years ago

What is the mass of a 5.00cm3 piece of copper having a density of 8.96g/cm3

r-ruslan [8.4K]

Answer:

44.8 grams

Explanation:

The density exists as a ratio comparing the mass of a piece of copper per 1 cm³. Since you have been given a new volume, you can set up a proportion to find the new mass.

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