<span>Uniform. A parallel plate capacitor is a simple arrangement of electrodes and dielectric to form a capacitor. Here two parallel conductive plates are used as electrodes with a medium or dielectric in between them. Charge separation in a parallel-plate capacitor causes an internal electric field, which is uniform.</span>
Answer:
a. The thickness of the wire is 2.5 mm.
b. The wire is 0.25 cm thick.
Explanation:
Number of turns of the wire = 10
The length of total turns = 25 mm
a. The thickness of the wire can be determined by;
thickness of the wire = 
= 
= 2.5 mm
Therefore, the wire is 2.5 mm thick.
b. To determine the thickness of the wire in centimetre;
10 mm = 1 cm
So that,
2.5 mm = x
x = 
= 0.25 cm
The wire is 0.25 cm thick.
Answer:
(C) Decreases by factor of 3
Explanation:
Centripetal acceleration is given by

where <em>v</em> is the linear velocity and <em>r</em> is the radius of the curve.
Let the centripetal acceleration on the curve of radius <em>R</em> be
.
Then

Let the centripetal acceleration on the curve of radius 3<em>R</em> be
.
Then

Here, we see that the acceleration decreases by a factor of 3.
Inorganic chemical compounds
Explanation:
Inorganic chemical compounds employ the use of oxidation numbers of atoms to write their chemical formula.
- The oxidation number is the formal charge assigned assigned to an atom present in a molecule or formula unit or ion based on some rules.
- Knowledge of this number is used in writing the formulae of inorganic compounds.
- These compounds forms by the exchange of certain small whole numbers by atoms or groups of atoms.
- The combining power usually correspond to the number of electrons usually lost or gained or shared by atoms of elements during chemical combinations or the number of positive or negative charges carried by ions.
For example:
A B
combining power(Valency): X Y
Exchange of valencies Y X
Molecular formula of compound A
Bₓ
Learn more:
Compounds brainly.com/question/5961886
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Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :


F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :


P = 0.202 Pa
Hence, this is the required solution.