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lara [203]
3 years ago
10

A 2.61 g sample of a substance suspected of being pure gold is warmed to 72.8 ∘C and submerged into 15.8 g of water initially at

24.9 ∘C. The final temperature of the mixture is 26.1 ∘C. What is the specific heat capacity of the unknown substance (in J/g*ºC)?
Chemistry
1 answer:
Likurg_2 [28]3 years ago
5 0
 <span>mg = 2.42 g 
Tg = 72.2 deg.C 
mw = 15.8 g 
Tw = 24.5 
Tf = 27 deg. C 
Cw = 4.18 J/g. deg. C 

Energy balance for insulated system, 
ΔE = 0 
ΔUw + ΔUg = 0 
ΔUw = - ΔUg 
Qin = Qout 
mg*cg*ΔTg = mw*cw*ΔTw 
2.42*cg*(72.2 - 27) = 15.8*4.18*(27 - 24.5) 
cg = 1.5095 J/g. deg.C or 1.5095 J/g.K</span><span>
</span>
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The two isotopes of uranium that are most commonly found in nature are U-235 and U-238. The 'fission' or breaking of the U-235 atoms, which releases energy in the form of heat, is how nuclear reactors generate energy. The primary fissile isotope of uranium is U-235.

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There is some interest in increasing the level of enrichment to around 7%, and even over 20% for particular special power reactor fuels, as high-assay LEU (HALEU).

Although uranium-235 and uranium-238 are chemically identical, they have different physical characteristics, most notably mass. The U-235 atom has an atomic mass of 235 units due to its 92 protons and 143 neutrons in its nucleus. The U-238 nucleus has 146 neutrons—three more than the U-235 nucleus—in addition to its 92 protons, giving it a mass of 238 units.

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