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docker41 [41]
3 years ago
14

Integral of (x^2)/(e^x^3)

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

I=\displaystyle\int\frac{x^2}{e^{x^3}}\,\mathrm dx

Substitute y=x^3 and \mathrm dy=3x^2\,\mathrm dx. Then

I=\displaystyle\frac13\int\frac{\mathrm dy}{e^y}=-\frac1{3e^y}+C=-\frac1{3e^{x^3}}+C

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