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docker41 [41]
3 years ago
14

Integral of (x^2)/(e^x^3)

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

I=\displaystyle\int\frac{x^2}{e^{x^3}}\,\mathrm dx

Substitute y=x^3 and \mathrm dy=3x^2\,\mathrm dx. Then

I=\displaystyle\frac13\int\frac{\mathrm dy}{e^y}=-\frac1{3e^y}+C=-\frac1{3e^{x^3}}+C

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Will give brainliest to correct answer.
kirill [66]
It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this.  That will look like this: (2 \sqrt{x} +1)^2=( \sqrt{x} +1)^2+(2 \sqrt{x} )^2.  FOIL out the left side to get 4x+4 \sqrt{x} +1.  FOIL out the first of the 2 expressions on the right to get x+2 \sqrt{x} +1,  and the second of the 2 to get 4x.  Our equation now looks like this:  4x+4 \sqrt{x} +1=x+2 \sqrt{x} +1+4x.  Combine like terms to get an equation that still has square roots in it that we have to deal with:  4x-x-4x=-2 \sqrt{x}  and x=2 \sqrt{x}.  We will square both sides to get rid of the square root sign.  x^{2} =2x.  This is a polynomial now that can be factored to solve for x.  Bring the 2x over by subtraction and set the polynomial equal to 0.  x^{2} -2x=0.  Factor out an x, leaving us with  x(x-2)=0.  That means that x = 0 or x - 2 = 0 and x = 2.  Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2.  x = 2
3 0
3 years ago
Read 2 more answers
HELP 40 POINTS
Tom [10]
Answer: the function g(x) has the smallest minimum y-value.


Explanation:


1) The function f(x) = 3x² + 12x + 16 is a parabola.


The vertex of the parabola is the minimum or maximum on the parabola.


If the parabola open down then the vertex is a maximum, and if the parabola open upward the vertex is a minimum.


The sign of the coefficient of the quadratic term tells whether the parabola opens upward or downward.


When such coefficient is positive, the parabola opens upward (so it has a minimum); when the coefficient is negative the parabola opens downward (so it has a maximum).


Here the coefficient is positive (3), which tells that the vertex of the parabola is a miimum.


Then, finding the minimum value of the function is done by finding the vertex.

I will change the form of the function to the vertex form by completing squares:

Given: 3x² + 12x + 16

Group: (3x² + 12x) + 16
Common factor: 3 [x² + 4x ] + 16
Complete squares: 3[ ( x² + 4x + 4) - 4] + 16
Factor the trinomial: 3 [(x + 2)² - 4] + 16
Distributive property: 3 (x + 2)² - 12 + 16
Combine like terms: 3 (x + 2)² + 4

That is the vertex form: A(x - h)² + k, whch means that the vertex is (h,k) = (-2, 4).


Then the minimum value is 4 (when x = - 2).


2) The othe function is <span>g(x)= 2 *sin(x-pi)
</span>

The sine function goes from -1 to + 1, so the minimum value of sin(x - pi) is - 1.


When you multiply by 2, you just increased the amplitude of the function and obtain the new minimum value is 2 (-1) = - 2


Comparing the two minima, you have 4 vs - 2, and so the function g(x) has the smallest minimum y-value.

7 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
schepotkina [342]
I need you to be more specific
8 0
3 years ago
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Tuition is $29,637. increase is 5.1%. what is new cost?​
Veseljchak [2.6K]

Answer:

31,148.48

Step-by-step explanation:

29,637*.051= 1,511.48

29,637+1,511.48=31,148.48

6 0
3 years ago
Which data value has the highest frequency?<br><br> 116<br><br> 316<br><br> 38<br><br> 58
lara31 [8.8K]
1/16.  that is the value that has the most x's on the graph.
8 0
3 years ago
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