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docker41 [41]
3 years ago
14

Integral of (x^2)/(e^x^3)

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

I=\displaystyle\int\frac{x^2}{e^{x^3}}\,\mathrm dx

Substitute y=x^3 and \mathrm dy=3x^2\,\mathrm dx. Then

I=\displaystyle\frac13\int\frac{\mathrm dy}{e^y}=-\frac1{3e^y}+C=-\frac1{3e^{x^3}}+C

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Answer:

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7 0
3 years ago
The figure below has a height of 18 inches and a volume of 864 cubic inches. What is the area of the base of the figure? A. 7776
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5 0
3 years ago
Joe has 17 coins, nickels and dimes, that total up to $1.25. How many nickels does he have?
kifflom [539]

Answer:

9 nickels

Step-by-step explanation:

He has 17 coins.

$1.25 is 12 dimes and 1 nickel. But that is only 13 coins.

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6 0
4 years ago
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Bad White [126]
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6 0
3 years ago
Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds
Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

Poor risk = 2839

Probabilty that the ball choosen at random is not poor= 1 - probability that the ball is poor

Probability of poor = 2839/11332

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Probabilty that the ball choosen at random is not poor= 1- 0.2505

= 0.7495

To two decimal place= 0.75

3 0
3 years ago
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