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galben [10]
3 years ago
5

As the temperature of a fluid decreases— A The number of inter-particle collisions decrease and random movement of particles inc

rease. B The number of inter-particle collisions and random movement of particles decrease. C The number of inter-particle collisions and random movement of particles increase. D The number of inter-particle collisions increase and random movement of particles decrease.
Physics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

Only option 'B' is correct

Explanation:

Other options are not totally correct. The molecular collision and random movement of particles are proportional so they both decrease in this condition. Thank you.

Alika [10]3 years ago
3 0

Answer:

Option B The number of inter-particle collisions and random movement of particles decrease.

Explanation:

According to the kinetic theory of gas,

The average kinetic energy of gas molecules are directly proportional to the temperature. This means that an increase in temperature will give the gas molecules more energy to move randomly and a decrease in the temperatures will also decrease the energy of the molecules hence decreasing their random movement. Also, as the temperature increases, and the gas molecules moves more randomly, they collide more with each other and as the temperature decrease, and their random movement also decrease, the collision of the gas molecules also decrease.

Now from the question given above,

As the temperature of a fluid decreases, the number of inter-particle collisions and random movement of particles decrease.

So, option B is the correct option.

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almond37 [142]

Answer:

μ = 0.0315

Explanation:

Since the car moves on a horizontal surface, if we sum forces equal to zero on the Y-axis, we can determine the value of the normal force exerted by the ground on the vehicle. This force is equal to the weight of the cart (product of its mass by gravity)

N = m*g (1)

The friction force is equal to the product of the normal force by the coefficient of friction.

F = μ*N (2)

This way replacing 1 in 2, we have:

F = μ*m*g (2)

Using the theorem of work and energy, which tells us that the sum of the potential and kinetic energies and the work done on a body is equal to the final kinetic energy of the body. We can determine an equation that relates the frictional force to the initial speed of the carriage, so we will determine the coefficient of friction.

\frac{1}{2} *m*v_{i}^{2}-(F*d)=  \frac{1}{2} *m*v_{f}^{2}

where:

vf = final velocity = 0

vi = initial velocity = 85 [km/h] = 23.61 [m/s]

d = displacement = 900 [m]

F = friction force [N]

The final velocity is zero since when the vehicle has traveled 900 meters its velocity is zero.

Now replacing:

(1/2)*m*(23.61)^2 = μ*m*g*d

0.5*(23.61)^2 = μ*9,81*900

μ = 0.0315

5 0
3 years ago
You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont
Rashid [163]

Answer:

47.48 m

Explanation:

The horizontal range of an object can be estimated using the equation below:

S_{x} =\frac{v^{2}*sin (2\alpha)}{g}

For the maximum horizontal range to occur, the angle \alpha is 45°. Then, the horizontal range will be:

S_{x} = \frac{v^{2}*sin 90}{g} = \frac{v^{2}}{g}

In addition, the velocity (v) can be estimated using the equation below:

v = gt/2

Therefore, the maximum horizontal range is:

S_{x} =  \frac{(gt/2)^{2}}{g} = (9.81*4.4/2)^2 / 9.81 = 47.48 m

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3 years ago
How many oxygen (O) atoms are in a molecule of Cg H,O3?<br> A. 1<br> B. 3<br> C. 10<br> D. 4
nikklg [1K]

Answer:

B. 3

Explanation:

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2 years ago
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3 years ago
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A truck moving at 20 mph shoots a soccer ball at 20 mph in the opposite direction. How fast is the soccer ball moving? Explain
Brrunno [24]

Answer:

Speed of the soccer ball with respect to ground is ZERO

Explanation:

As we know that truck is moving with speed 20 mph

Now a soccer ball is shoot from truck with respect to the motion of truck in opposite direction

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now we know that

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