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galben [10]
3 years ago
5

As the temperature of a fluid decreases— A The number of inter-particle collisions decrease and random movement of particles inc

rease. B The number of inter-particle collisions and random movement of particles decrease. C The number of inter-particle collisions and random movement of particles increase. D The number of inter-particle collisions increase and random movement of particles decrease.
Physics
2 answers:
Alenkasestr [34]3 years ago
7 0

Answer:

Only option 'B' is correct

Explanation:

Other options are not totally correct. The molecular collision and random movement of particles are proportional so they both decrease in this condition. Thank you.

Alika [10]3 years ago
3 0

Answer:

Option B The number of inter-particle collisions and random movement of particles decrease.

Explanation:

According to the kinetic theory of gas,

The average kinetic energy of gas molecules are directly proportional to the temperature. This means that an increase in temperature will give the gas molecules more energy to move randomly and a decrease in the temperatures will also decrease the energy of the molecules hence decreasing their random movement. Also, as the temperature increases, and the gas molecules moves more randomly, they collide more with each other and as the temperature decrease, and their random movement also decrease, the collision of the gas molecules also decrease.

Now from the question given above,

As the temperature of a fluid decreases, the number of inter-particle collisions and random movement of particles decrease.

So, option B is the correct option.

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steposvetlana [31]

To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.

Mathematically the expression is given as

I = I_0 cos^2\theta

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I = Final Intensity after pass through the polarizer

\theta= Angle between the polarizer and the light

Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as

\frac{I}{I_0} = \frac{1}{2}

Using the Malus Law we have,

I = I_0 cos^2\theta

cos^2\theta = \frac{I}{I_0}

cos^2\theta = \frac{1}{2}

\theta = cos^{-1}(\frac{1}{2})^2

\theta = 75.52\°

Angle with respect to maximum is 90-75.52 = 14.48\°

8 0
2 years ago
Two identical conducting spheres, A and B, carry equal charge. They are separated by a distance much larger than their diameters
Vesnalui [34]

Answer:

C. \frac{3F}{8}

Explanation:

Let initial charges on both spheres be,q

F=\frac{Kq^2}{d^2}   \ \ \  \ \ \  \ \ \  \ \_i

When the sphere C is touched by A, the final charges on both will be,\frac{q}{2}

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q_c=q_d=\frac{q/2+q}{2}\\\\=\frac{3q}{4}\\

Now the force between A and B is calculated as:

F\prime=\frac{k\times\frac{q}{2}\times \frac{3q}{4}}{d^2}\\F\prime=\frac{3F}{8}

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4 0
3 years ago
If the mass of a
mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

F=ma

m = mass

a = acceleration

According to given condition, if the mass of a  sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

a=\dfrac{F}{m}

Let a' is the final acceleration,

a'=\dfrac{F}{m'}

m' = 3m

a'=\dfrac{F}{3m}

a'=\dfrac{1}{3}\times \dfrac{F}{m}

a'=\dfrac{1}{3}\times a

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0
3 years ago
Now, find the concentration of H+ ions to OH– ions listed in Table B of your Student Guide for a solution at a pH = 11. Then div
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Answer

1.0/5

4

IlaMends

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Explanation:

When pH of the solution is 11.

..(1)

At pH = 11, the concentration of ions is .

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At pH = 6, the concentration of ions is .

On dividing (1) by (2).

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This means that Hydrogen ions in a solution at pH = 7 has ions fewer than in a solution at a pH = 6

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2 years ago
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