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Hunter-Best [27]
3 years ago
11

It is a cold night around the campfire. Megan is trying to get warm by sitting close to the fire and clutching her mug of hot ch

ocolate. How is heat being transferred to chilly Megan?
Physics
1 answer:
lions [1.4K]3 years ago
6 0
The heat of the fire is warming her skin by making the air hot while drinking the hot chocolate warms her from inside of her
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Which statement describes why energy is released in a nuclear fission reaction based on mass-energy equivalence?
lawyer [7]

Answer:

A is the answer!

Explanation:

Edge 2021

9 0
3 years ago
1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into
Aleksandr [31]

Answer:

  even if it all could be used, it wouldn't be enough

Explanation:

The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.

Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.

8 0
4 years ago
A light, flexible cable is wrapped around a solid cylinder with mass 3.3 kg and a radius of 0.8 meters. The cylinder rotates on
kari74 [83]

Answer:

9.16rad/s^2

Explanation:

We are given that

Mass,m_1=3.3 kg

Radius,r=0.8 m

m_2=4.9 kg

Height,h=2.9 m

We have to find the angular acceleration of the cylinder.

According to question

4.9g-T=4.9a

Tr=I\alpha

Where

\alpha=\frac{a}{r}

Tr=\frac{1}{2}m_1ra

T=\frac{1}{2}m_1a=\frac{1}{2}(3.3)a

Substitute the value

4.9g-\frac{1}{2}(3.3a)=4.9a

4.9\times 9.8=4.9a+\frac{3.3a}{2}

Where g=9.8 m/s^2

48.02=a(4.9+1.65)=6.55a

a=\frac{48.02}{6.55}=7.33m/s^2

Angular acceleration,\alpha=\frac{a}{r}=\frac{7.33}{0.8}=9.16rad/s^2

7 0
3 years ago
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 296o
Schach [20]

Explanation:

The given data is as follows.

       Temperature of metal = 296^{o}C = (296 + 273) K

                                            = 569 K

     Density of the metal = 8.85 g/cm^{3} = 8.85 \times 10^{-6} g/m^{3}      (as 1 cm^{3} = 10^{-6} m^{3})

     Atomic mass = 51.40 g/mol

    Vacancies = 9.19 \times 10^{23} m^{-3}

Formula to calculate the number of atomic sites is as follows.

           n = \frac{\rho \times N_{A}}{\text{atomic weight}}

              = \frac{8.85 \times 10^{-6} \times 6.022 \times 10^{23}}{51.40 g/mol}

              = 1.036 \times 10^{17} atom/m^{3}

Now, we will calculate the energy as follows.

                E = -KT \times ln (\frac{\text{no. of vacancies}}{\text{no. of atomic sites}})

where,    K = 8.62 \times 10^{-5}

         E = -8.62 \times 10^{-5} \times 569 K \times ln (\frac{9.19 \times 10^{23}}{1.036 \times 10^{17} atom/m^{3}})

               = 78.46 eV/atom

Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is 78.46 eV/atom.

6 0
4 years ago
Sources of error in a diverging lens experiment ​
Snezhnost [94]

Answer:

Lens and the virtual image was the image distance. Error was made when measuring the distances and determining values that were reasonable for focal length, so this error was accounted for when calculating the focal length by adding or subtracting uncertainties from the values.Plane mirrors, convex mirrors, and diverging lenses can never produce a real image. A concave mirror and a converging lens will only produce a real image if the object is located beyond the focal point (i.e., more than one focal length away). 5.

3 0
3 years ago
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