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Bogdan [553]
3 years ago
7

The total resistance of resistors in parallel is always _________ the sum of the resistors.

Physics
2 answers:
docker41 [41]3 years ago
7 0
A. less than

In fact, the resistance will be less than that of the lowest resistance resistor.
pashok25 [27]3 years ago
7 0
A.) The total resistance of resistors in parallel is always "Less than" <span>the sum of the resistors.

Hope this helps!</span>
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If some raps 3words per second then how many words would he say in 9,999,999,990 seconds ​
wolverine [178]

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29,999,999,970 words

Explanation:

9,999,999,990x3

3 0
3 years ago
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Is condensation adding thermal energy
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I believe it is, since the heat causes the water to evaporate and cause condensation,
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A circuit is constructed with six resistors and two batteries as shown. the battery voltages are v1 = 18 v and v2 = 12 v. the po
VladimirAG [237]

Answer:

V4=9.197v

Explanation:

Given:

V1= 18v ,V2= 12v ,r1=r5=58ohms ,r2=r6=124ohms , r3=47ohms ,r4= 125ohms

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5 0
3 years ago
An office window has dimensions 3.1 m by 2.1 m. As a result of the passage of a storm, the outside air pressure drops to 0.954 a
Virty [35]

Answer:

Net forces which pushes the window is 30342.78 N.

Explanation:

Given:

Dimension of the office window.

Length of the window = 3.1 m

Width of the window = 2.1 m

Area of the window = (3.1\times 2.1) = 6.51\ m^2

Difference in air pressure = Inside pressure - Outside pressure

                                           = (1.0-0.954) atm = 0.046 atm

Conversion of the pressure in its SI unit.

⇒  1 atm = 101325 Pa

⇒ 0.046 atm = 0.046\times 101325 =4660.95 Pa

We have to find the net force.

We know,

⇒ Pressure = Force/Area

⇒ Pressure=\frac{Force }{Area}

⇒ Force =Pressure\times Area

⇒ Plugging the values.

⇒ Force =4660.95\times 6.51

⇒ Force=30342.78 Newton (N)

So,

The net forces which pushes the window is 30342.78 N.

3 0
3 years ago
A carriage of 20 kg is pulled with a force of 35 N. How far the carriage will go
Gennadij [26K]

Answer:

2.71 m

Explanation:

Force is the product of mass and acceleration

F=m*a

Work done is the product of force and distance

Work done=F*d

In this case;

F= 35 N

Work done = 95 J

95 =35 * d

95 /35 = d

2.71 m= d

6 0
3 years ago
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