To fill up all of the valence electrons we must have 8 electrons total to have an ionic bond. In this case Lithium is in group 1 and so only has 1 valence electron and so it can bond with elements from group 17, since 7 + 1 = 8. However, this unknown element did bond with beryllium, and beryllium is in group 2 so it must bond with an atom that has 6 valence electrons. The elements that have 6 valence electrons are in group 16 not group 2. So the result does not support her conclusion.
Answer:
The frictional force the road applies to the rear tire is static friction and it acts opposite to the direction in which the car is traveling.
Explanation:
This question suggests that the car is accelerating forward. Thus, the easiest way for us to know what friction is doing is for us to know what happens when we turn friction off.
Now, if there is no friction and the car is stopped, if we push down on the accelerator, it will make the front wheels to spin in a clockwise manner. This spin occurs on the frictionless surface with the rear wheels doing nothing while the car doesn't move.
Now, if we apply friction to just the front wheels, the car will accelerate forward while the back wheels would be dragging along the road and not be spinning. Thus, friction opposes the motion and as such, it must act im a direction opposite to where the car is going. This must be static friction.
The frictional force the road applies to the rear tire is static friction and it acts opposite to the direction in which the car is traveling.
these are the answer options
They experienced a renewed economy.
They joined the European Union.
They suffered genocide.
They gained control of Yugoslavia.
the correct answer is they suffered a genocide
communisum fell in Yugoslavia in 1990 Bosnia had their genocide in 1992
Yugoslavia broke into six sections 1945 one including Bosnia
bosnia still has not joined the EU
also i took the test and it was correct
Answer:
E₂ / E₁ = 521.64 / 5.95 =87.67
Explanation:
Let d be the distance covered inside electric field . Lt q be the magnitude of charge.
Force under field E₁ = q E₁
acceleration = qE₁/ m
d = 1/2 a t²
d = .5 ( qE₁ / m) x 32.3²
d = 521.64 ( qE₁ / m)
Similarly for return journey,
d = .5 x ( qE₂ / m) x 3.45²
d = 5.95x( qE₂ / m)
521.64 ( qE₁ / m) = 5.95x( qE₂ / m)
E₂ / E₁ = 521.64 / 5.95 =87.67
Yhuihoifjhh <span>F = Gm1m2 / r^2
if the masses are doubled then the force is increased by a factor of 4
if the distance is doubled the force is decreased by a factor of 1/ 2^2
the net result is no change in force</span>