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4 years ago

1

Mathematics

2 answers:

NeTakaya4 years ago

6 0

Answer:

It's option A. Just got it right on edge 2020

Step-by-step explanation:

ANTONII [103]4 years ago

5 0

Answer:

Step-by-step explanation:

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The circle below is centered at the point (4, 1) and has a radius of length 2 What is its equation?

11111nata11111 [884]

Answer:

(x - 4)^2 + (y - 1)^2 = 2^2 = 4

Step-by-step explanation:

The applicable equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2. Here, h = 4; k = 1; and r = 2.

So the desired equation is (x - 4)^2 + (y - 1)^2 = 2^2

6 0

3 years ago

Which three-dimensional figures have lateral faces that are polygons? Check all that apply. cones cylinders hemispheres prisms p

lyudmila [28]

Answer:

Prisms

Pyramids

Step-by-step explanation:

Lateral faces of a pyramid are triangles (3 sided polygon)

Lateral faces of prisms are rectangles (4 sides polygon)

8 0

3 years ago

How will knowing the value for the best measure of center for the heights of the adult males help Nancy determine whether she ca

uranmaximum [27]

Answer:

If Nancy only used the mean, then outliers could make her calculations inaccurate. By using an appropriate measure of center, Nancy is more likely to select clothing sizes that will fit the population of the countries she is sending clothing to.

Step-by-step explanation

From the app

8 0

3 years ago

Consider the quadratic function f(x) = -x^2 + 1x + 12. Determine the following: (enter all numerical answers as integers, fracti

vovikov84 [41]

Answer and Explanation:

Given : The quadratic function $f(x)=-x^2+x+12$

To find : Determine the following ?

Solution :

The x -intercept are where f(x)=0,

So, $-x^2+x+12=0$

Applying middle term split,

$-x^2+4x-3x+12=0$

$-x(x-4)-3(x-4)=0$

$(x-4)(-x-3)=0$

$x=4,-3$

The x-intercepts are (4,0) and (-3,0).

The smallest x-intercept is x=-3

The largest x-intercept is x=4

The y -intercept are where x=0,

So, $f(0)=-(0)^2+0+12$

$f(0)=12$

The y-intercept is y=12.

The quadratic function is in the form, $y=ax^2+bx+c$

On comparing, a=-1 , b=1 and c=1 2

The vertex of the graph is denote by (h,k) and the formula to find the vertex is

For h, The x-coordinate of the vertex is given by,

$h=-\frac{b}{2a}$

$h=-\frac{1}{2(-1)}$

$h=\frac{1}{2}$

For k, The y-coordinate of the vertex is given by,

$k=f(h)$

$k=-h^2+h+12$

$k=-(\frac{1}{2})^2+\frac{1}{2}+12$

$k=-\frac{1}{4}+\frac{1}{2}+12$

$k=\frac{-1+2+48}{4}$

$k=\frac{49}{4}$

The vertex of the function is $(h,k)=(\frac{1}{2},\frac{49}{4})$

The x-coordinate of the vertex i.e. $x=-\frac{b}{2a}$ is the axis of symmetry,

So, $x=-\frac{b}{2a}=\frac{1}{2}$ (solved above)

The axis of symmetry is $x=\frac{1}{2}$ .

4 0

4 years ago

SHOW ALL WORK<br> What is y

azamat

Answer:

Sir, I cant tell you the answer until I can see the equation, and the image provided isn't loading.

Step-by-step explanation:

3 0

3 years ago