Question

Four point charges are placed at the corners of a square. Each charge has the identical value +Q. The length of the diagonal of the square is 2a.
What is the electric potential at the center of the square?

Answer 1

Answer:$V_{net}=4\frac{kQ}{a}$    

Explanation:

Given

charge on each Particle is Q

Length of diagonal of the square is 2a

therefore distance between center and each charge is $\frac{2a}{2}=a$

Electric Potential of charged Particle is given by

For First Charge

$V_1=\frac{kQ}{a}$

$V_2=\frac{kQ}{a}$

$V_3=\frac{kQ}{a}$

$V_4=\frac{kQ}{a}$

total Electric Potential At center is given by

$V_{net}=V_1+V_2+V_3+V_4$

$V_{net}=4\times \frac{kQ}{a}$

$V_{net}=4\frac{kQ}{a}$