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Mandarinka [93]
3 years ago
8

Describe two experiments to determine the speed of propagation of a transverse wave on a rope. You have the following tools to u

se: a stopwatch, a meter stick, a mass-measuring scale, and a force-measuring device. Use whatever other items you need for your experiments.
Physics
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

#See solution for details.

Explanation:

1.

Tools:stopwatch, \ meter \ stick, \ mass \ measuring \ scale , \ force \ measuring  \ device.

Experiment \ 1:Calculate the speed of the wave using the time,t it takes to travel along the rope. Rope's length,L is measured using the meter stick.

-Attach one end of rope to a wall or post, shake from the unfixed end to generate a pulse. Measure the the time it takes for the pulse to reach the wall once it starts traveling using the stopwatch.

-Speed of the pulse can then be obtained as:

v=\frac{L}{t}

Experiment \ 2: Apply force of known value to the rope then use the following relation equation to find the speed of a pulse that travels on the rope.

v=\sqrt{\frac{F}{\mu}}\ ,\mu=\frac{m}{L}

-Use the measuring stick and measuring scale to determine L,m values of the rope then obtain \mu.

-Use the force measuring constant to determine F. These values can the be substituted in Experiment \ 1 to obtain v.

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Answer:

 Δt'/ T% = 90.3%

Explanation:

Simple harmonic movement is described by the expression

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we find the time for the two points of motion

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remember that angles are in radians

        w t₁ = 1.875 rad

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        0.3 A = A cos w t₂

        w t₂ = cos -1 (0.3)

         w t₂ = 1,266 rad

         

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x= -A

        w t₃ = cos⁻¹ (-1)

        w t₃ = π rad

this angle for the forward movement and the same time for the return movement in the oscillation to the same point, which is the definition of period

         T = 2 t₃

         T = 2π / w     s

now we can calculate the fraction of time in the given time interval

        Δt / T = (t₁ -t₂) / T

        Δt / T = (1,875 - 1,266) / 2pi

        Δt / T = 0.0969

 

This is the fraction for when the mass is from 0 to 0.3, for regions of oscillation of greater amplitude the fraction is

         Δt'/ T = 1 - 0.0969

         Δt '/ T = 0.903

         Δt'/ T% = 90.3%

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